python - 计算列表中具有相同值的子列表

Question

如何计算列表中具有相同值(顺序无关紧要)的子列表？

我试过这个:

from collections import Counter

Input = [
    [
        'Test123', 'heyhey123', 'another_unique_value',
    ],
    [
        'Test123', 'heyhey123', 'another_unique_value',
    ],
    [
        'heyhey123',
    ],
    [
        'Test123', 'heyhey123',
    ],
    [
        'another_unique_value', 'heyhey123', 'Test123'
    ]
]

Counter(str(e) for e in li)

Output:

Counter({
    "['Test123', 'heyhey123', 'another_unique_value']": 2},
    "['heyhey123']": 1},
    "['Test123', 'heyhey123']": 1},
    "['another_unique_value', 'heyhey123', 'Test123']": 1},
)

显然，它从列表中的值中获取顺序。如何计算顺序无关紧要的子列表？

我想要的输出是:

Counter({
    "['Test123', 'heyhey123', 'another_unique_value']": 3},
    "['heyhey123']": 1},
    "['Test123', 'heyhey123']": 1},
)

Answer 1

可以替换

Counter(str(e) for e in li)

与

Counter(tuple(sorted(e)) for e in li)

给出输出:

Counter({('Test123', 'another_unique_value', 'heyhey123'): 3,
         ('heyhey123',): 1,
         ('Test123', 'heyhey123'): 1})

另一种选择是使用 set(e) 忽略列表中元素的顺序，但这有忽略重复的缺点 - ['Test123', 'heyhey123' , 'another_unique_value'] 将被视为与 ['Test123', 'heyhey123', 'another_unique_value', 'another_unique_value'] 相同 - 此外，当从不可散列的set 包含在 Counter 中，不保证相同的顺序。