react-native - 如何在运行时在 react-native-mapbox-gl 中显示/隐藏光栅层(可见性属性可见/无)

Question

我在 map 初始化中设置了自定义样式 url。喜欢 :

<Mapbox.MapView
   styleURL="asset://mystyle.json"
   logoEnabled={false}
   attributionEnabled={false}
   ref={(e) => { this.oMap = e }}
   animate={true}
   zoomLevel={6}
   centerCoordinate={[54.0, 24.0]}
   style={{ flex: 1 }}
   showUserLocation={true}>
</Mapbox.MapView>

在 mystyle.json 我有两个 basemap ，如下所示:

 {
      "id": "Satellite",
      "type": "raster",
      "source": "Satellite",
      "layout": {
        "visibility": "visible"
      },
      "paint": {
        "raster-opacity": 1
      }
    },
 {
      "id": "Satellite2",
      "type": "raster",
      "source": "Satellite",
      "layout": {
        "visibility": "none"
      },
      "paint": {
        "raster-opacity": 1
      }
    }

卫星是可见的默认。

如何在运行时将卫星属性的可见性设置为无并将卫星 2 的可见性设置为可见？

map 箱gl:

"@mapbox/react-native-mapbox-gl": "^6.1.3"

react 原生:

"react-native": "0.58.9",

Answer 1

最后我得到了解决方案:

constructor() {
   this.state = {
      lightMap: 'visible', 
      darkMap: 'none'
   };
} 

changeMap(){
   this.setState({darkMap:'visible'})
}

<MapboxGL.MapView
   styleURL="asset://mystyle.json"
   logoEnabled={false}
   attributionEnabled={false}
   ref={(e) => { this.oMap = e }}
   zoomLevel={6}
   centerCoordinate={[54.0, 24.0]}
   style={{ flex: 1 }}>

<MapboxGL.RasterSource
   id="idLightMap" 
   url="LAYERURL1"
   tileSize={256}>
   <MapboxGL.RasterLayer 
      id="idLightMap"
      sourceID="idLightMap"
      style={{visibility: this.state.lightMap}}>
   </MapboxGL.RasterLayer>
</MapboxGL.RasterSource>

<MapboxGL.RasterSource
   id="idDarkMap" 
   url="LAYERURL2"
   tileSize={256}>
   <MapboxGL.RasterLayer
      id="idDarkMap"
      sourceID="idDarkMap"
      style={{visibility: this.state.darkMap}}>
   </MapboxGL.RasterLayer>
</MapboxGL.RasterSource>

</MapboxGL.MapView>

我添加了光栅层并以编程方式切换它。