arrays - 在 BASH 中为单词数组添加边框

Question

我一直在学习 Bash，我的老师做了一个让我感到困惑的练习。

我只是在努力在单词前面添加空格。

代码应考虑到每个单词中的字符数，并调整星号和间距的数量以使其始终对齐。

它应该是这样的:

***********
* Hello   *
* World   *
* good    *
* etceter *
***********

我的代码:

#determine biggest word
words=("Hello" "World" "good" "etceter")
numchar=0
for i in ${words[@]}; do
    if [ ${#i} -gt $numchar ]
    then
        numchar=${#i}
    fi
done

#write *
a=-4
while [ $a -lt $numchar ]; do
    printf "*"
    ((a++))
done

#write array
echo
for txt in ${words[@]}; do
    space=$(($numchar-${#txt}))
    s=0
    echo "* $txt "
    while [ $s -lt $space ]; do
        printf " "
        ((s++))
        printf "*"
    done
done

#write *
a=-4
while [ $a -lt $numchar ]; do
    printf "*"
    ((a++))
done

我正在努力处理#write 数组部分。

非常感谢!

Answer 1

您只需要进行一些更改。

#write array
echo
for txt in ${words[@]}; do
    space=$(($numchar-${#txt}))
    s=0
    echo -n "* $txt "           # -n added to not append a newline
    while [ $s -lt $space ]; do
        echo -n " "             # switched from printf to echo (cosmetics)
        ((s++))
        # printf "*"            # commented out
    done
    echo "*"                    # added
done

您的 while 循环仅在当前单词后添加空格。结尾的 * 出现在结束这一行的循环之后。