java - hibernate :参数索引超出范围(8>参数数量，即7)

Question

不是这个问题的重复Parameter index out of range (8 > number of parameters, which is 7)

我的SaltTranDef实体类别是

@Id
@Column(name="salt_id")
@GeneratedValue(strategy=GenerationType.IDENTITY)
private Integer saltId;

@Column(name="tran_type")
private String transactionType;

@Column(name="user_id")
private String userId;

@Column(name="parent_system")
private String parentSystem;

@Column(name="parent_sys_ref_id")
private String parentSystemReference;

@Column(name="status")
private int status;

@OneToMany(mappedBy = "saltTranDef")
@Cascade({ org.hibernate.annotations.CascadeType.ALL,
         org.hibernate.annotations.CascadeType.DELETE_ORPHAN })
private Set<SaltTranUser> saltTranUsers;

SaltTranUser实体类别为

@Id
@Column(name="salt_id")
private Integer saltId;

@Id
@Column(name="salt_property")
private String saltProp;

@Column(name="salt_value")
private String saltValue;

@ManyToOne
@JoinColumn(name="salt_id")
private SaltTranDef saltTranDef;

上面的两个实体类都扩展了mappingSuperclass

@Column(name="cre_suid")
private String creatorId;

@Column(name="mod_suid")
private String modifiedId;

@Column(name="cre_date")
private Timestamp creationDate;

@Column(name="mod_date")
private Timestamp modificationDate;

从JUnit插入时:

@Test
public void testInsert(){

    SaltTranDef std = new SaltTranDef();
    SaltTranUser stu1 = new SaltTranUser();
    SaltTranUser stu2 = new SaltTranUser();
    SaltTranUser stu3 = new SaltTranUser();
    Set<SaltTranUser> set1 = new HashSet<SaltTranUser>();

    Transaction tx = session.beginTransaction();

    std.setParentSystem("A");
    std.setParentSystemReference("123");
    std.setStatus(10);
    std.setTransactionType("A");
    std.setUserId("1234");
    std.setCreationDate(new Timestamp(new Date().getTime()));
    std.setCreatorId("1234");

    session.persist(std);
//  session.flush();

    stu1.setCreationDate(new Timestamp(new Date().getTime()));
    stu1.setCreatorId("1234");
    stu1.setSaltProp("Fname");
    stu1.setSaltValue("Swateek");
    stu1.setSaltId(std.getSaltId());

    stu2.setCreationDate(new Timestamp(new Date().getTime()));
    stu2.setCreatorId("1234");
    stu2.setSaltProp("Lname");
    stu2.setSaltValue("Jena");
    stu2.setSaltId(std.getSaltId());

    stu3.setCreationDate(new Timestamp(new Date().getTime()));
    stu3.setCreatorId("1234");
    stu3.setSaltProp("Phone");
    stu3.setSaltValue("9900056668");
    stu3.setSaltId(std.getSaltId());

    set1.add(stu1);
    set1.add(stu2);
    set1.add(stu3);

    std.setSaltTranUsers(set1);

    session.save(std);
    tx.commit();
}

我收到一条错误消息:

SEVERE: Parameter index out of range (8 > number of parameters, which is 7). Mar 25, 2015 8:06:35 AM org.hibernate.event.def.AbstractFlushingEventListener performExecutions SEVERE: Could not synchronize database state with session org.hibernate.exception.GenericJDBCException: could not insert: [com.salt.entity.SaltTranUser] at org.hibernate.exception.SQLStateConverter.handledNonSpecificException(SQLStateConverter.java:103) Caused by: java.sql.SQLException: Parameter index out of range (8 > number of parameters, which is 7). at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1055)

Answer 1

这种问题几乎总是与双列映射有关。的确如此。我们可以看到，此映射两次使用一列两次 "salt_id" :
SaltTranUser实体类:

@Id
@Column(name="salt_id")
private Integer saltId;
...

@ManyToOne
@JoinColumn(name="salt_id")
private SaltTranDef saltTranDef;

那是错误的。 Hibernate最后将两次插入到一列中，即在INSERT，UPDATE列中添加更多的参数

这里的解决方案很可能非常简单-因为 @ManyToOne似乎是错误的。我希望有一些特殊的列可供引用，例如: SaltTranDef_id