oracle - ORA-13249 : SDO_NN cannot be evaluated without using index

Question

在 ORACLE 中运行以下 Sql 脚本时出现错误

SELECT D.ID
FROM  DOOR D
JOIN STREET S ON (S.ID=D.STREET_ID)
WHERE 
SDO_NN(D.LOCATION,SDO_UTIL.FROM_WKTGEOMETRY('POINT (11112.0111 321314.2222)'),'sdo_num_res=6') = 'TRUE'
or 
S.ID IN (17);

但是当我将“or”更改为“and”或删除“or S.ID IN (17)”时，我没有得到错误。

SELECT D.ID
FROM  DOOR D
JOIN STREET S ON (S.ID=D.STREET_ID)
WHERE 
SDO_NN(D.LOCATION,SDO_UTIL.FROM_WKTGEOMETRY('POINT (11112.0111 321314.2222)'),'sdo_num_res=6') = 'TRUE'
and 
S.ID IN (17);

DOOR 表中Location 字段的类型是MDSYS.SDO_GEOMETRY

和

STREET 表中ID 字段的类型是NUMBER

我希望第一个 SQL 能够工作。任何人都可以帮助解决这个问题吗？

Answer 1

提示有什么用吗？

SELECT /*+ LEADING(d) USE_NL(d s) INDEX s spatial_index) */
       D.ID
  FROM DOOR D JOIN STREET S ON (S.ID = D.STREET_ID)
 WHERE     SDO_NN (
              D.LOCATION,
              SDO_UTIL.FROM_WKTGEOMETRY ('POINT (11112.0111 321314.2222)'),
              'sdo_num_res=6') =
           'TRUE'
       AND S.ID IN (17);