ms-access - 如何在 MS-Access 中找到父窗口的宽度

Question

我试图强制 MS-Access 窗体相对于主窗口的右边缘占据某个位置(实际上我想将它居中，但我也可以看到想要将它停靠在一侧或另一侧)。我可以用 Me.Move 重新定位这个表单，例如，

    Me.Move newWindowLeft, newWindowTop, newWidth, newHeight

但是，我怎样才能知道父窗口的宽度？

Answer 1

您可以使用 Windows API:

(更新以返回缇)

Type Rect
    x1 As Long
    y1 As Long
    x2 As Long
    y2 As Long
End Type

Declare Function GetClientRect Lib "user32" (ByVal hwnd As Long, lpRect As Rect) As Long

Declare Function GetDC Lib "user32" (ByVal hwnd As Long) As Long

Declare Function ReleaseDC Lib "user32" (ByVal hwnd As Long, ByVal hdc As Long) As Long

Declare Function GetDeviceCaps Lib "gdi32" (ByVal hdc As Long, ByVal nIndex As Long) As Long

Const LOGPIXELSX = 88
Const LOGPIXELSY = 90
Const DIRECTION_VERTICAL = 1
Const DIRECTION_HORIZONTAL = 0

Public Function GetMainWindowSize()

    Dim MDIRect As Rect
    Dim lWidthPixels As Long
    Dim lWidthTwips As Long

    ' Get the screen coordinates and window size of the MDIClient area'
    GetClientRect Application.hWndAccessApp, MDIRect

    lWidthPixels = MDIRect.x2 - MDIRect.x1
    lWidthTwips = PixelsToTwips(lWidthPixels, DIRECTION_HORIZONTAL)

    MsgBox "Width (Pixels) = " & lWidthPixels & "  Width (Twips) = " & lWidthTwips

End Function


Function PixelsToTwips(lPixels As Long, lDirection As Long) As Long

    Dim lDeviceHandle As Long
    Dim lPixelsPerInch As Long

    lDeviceHandle = GetDC(0)

    If lDirection = DIRECTION_HORIZONTAL Then
        lPixelsPerInch = GetDeviceCaps(lDeviceHandle, LOGPIXELSX)
    Else

        lPixelsPerInch = GetDeviceCaps(lDeviceHandle, LOGPIXELSY)
    End If

    lDeviceHandle = ReleaseDC(0, lDeviceHandle)

    PixelsToTwips = lPixels * 1440 / lPixelsPerInch

End Function