macos - 如何在 AppleScript 中转义 shell 参数？

Question

Applescript 似乎没有正确转义字符串。我究竟做错了什么？

例子:

set abc to "funky-!@#'#\"chars"
display dialog abc
display dialog quoted form of abc

预期/期望输出:

funky-!@#'#"chars
'funky-!@#\'#"chars'

实际输出:

funky-!@#'#"chars
'funky-!@#'\''#"chars'

如您所见，在实际输出中，Applescript 似乎添加并转义了一个额外的 '
如果结尾字符是 '，我就可以了或 "而且我也可以对单引号和双引号进行转义 - 但似乎只有单引号实际上被转义了。

Answer 1

反斜杠通常不在 shell 中的单引号内解释。

Enclosing characters in single quotation marks preserves the literal value of each character within the single quotation marks. A single quotation mark cannot occur within single quotation marks.

A backslash cannot be used to escape a single quotation mark in a string that is set in single quotation marks. An embedded quotation mark can be created by writing, for example: 'a'\''b', which yields a'b.

然而，它们由 sh 中的 echo 解释，sh 是 do shell script 使用的 shell。 :

do shell script "echo " & quoted form of "\\t" --> "\t"

取消设置 xpg_echo使其表现得像 bash 中的 echo:

do shell script "shopt -u xpg_echo; echo " & quoted form of "\\t" --> "\\t"

通常使用 HEREDOC 重定向更简单:

do shell script "rev <<< " & quoted form of "a\\tb" --> "b\\ta"