python - 值错误 : Invalid character found in sheet title

Question

此 Python 代码失败:

from openpyxl import Workbook

wb = Workbook()
sheet = wb.create_sheet('*nice*')

异常(exception):

/home/foo/local/bin/python /home/foo/src/invalid.py
Traceback (most recent call last):
  File "/home/foo/src/invalid.py", line 5, in <module>
    sheet = wb.create_sheet('*nice')
  File "/home/foo/local/lib/python2.7/site-packages/openpyxl/workbook/workbook.py", line 158, in create_sheet
    new_ws = Worksheet(parent=self, title=title)
  File "/home/foo/local/lib/python2.7/site-packages/openpyxl/worksheet/worksheet.py", line 121, in __init__
    _WorkbookChild.__init__(self, parent, title)
  File "/home/foo/local/lib/python2.7/site-packages/openpyxl/workbook/child.py", line 50, in __init__
    self.title = title or self._default_title
  File "/home/foo/local/lib/python2.7/site-packages/openpyxl/workbook/child.py", line 93, in title
    raise ValueError(msg)
ValueError: Invalid character * found in sheet title

如何创建标题中包含*的工作表？

Answer 1

我们可以使用星号 (*) 符号创建工作表吗？

sheet = wb.create_sheet("&nice")

根据this ，我们不能在工作表名称中使用以下特殊字符

\/*[]:?