php - Symfony:注销后如何显示成功消息

Question

在Symfony中，用户成功登出后，如何显示“您已成功登出”之类的成功信息？

Answer 1

1) 创建一个新的服务来处理注销成功事件。

在 services.yml添加服务:

logout_success_handler:
    class: Path\To\YourBundle\Services\LogoutSuccessHandler
    arguments: ['@security.http_utils']

并添加类，替换 /path/to/your/login使用登录页面的 url(在 Controller 的最后一行):

<?php

namespace Path\To\YourBundle\Services;

use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\Security\Http\HttpUtils;
use Symfony\Component\Security\Http\Logout\LogoutSuccessHandlerInterface;

class LogoutSuccessHandler implements LogoutSuccessHandlerInterface
{
    protected $httpUtils;
    protected $targetUrl;

    /**
     * @param HttpUtils $httpUtils
     */
    public function __construct(HttpUtils $httpUtils)
    {
        $this->httpUtils = $httpUtils;

        $this->targetUrl = '/path/to/your/login?logout=success';
    }

    /**
     * {@inheritdoc}
     */
    public function onLogoutSuccess(Request $request)
    {
        $response = $this->httpUtils->createRedirectResponse($request, $this->targetUrl);

        return $response;
    }
}

2) 配置您的 security.yml使用自定义 LogoutSuccessHandler刚刚创建:

firewalls:
    # ...
    your_firewall:
        # ...
        logout:
            # ...
            success_handler: logout_success_handler

3)在登录页面的 Twig 模板中添加:

{% if app.request.get('logout') == "success" %}
    <p>You have successfully logged out!</p>
{% endif %}