ruby-on-rails - Rails - ActiveAdmin 和 Papertrail - 一种 DRY 方法

Question

我有很多使用 PaperTrail 的模型，例如:

class User < ActiveRecord::Base
  has_paper_trail
end

在我的 ActiveAdmin 模型文件中:

ActiveAdmin.register User do

  ...

  # versioning part
  action_item :history, only: :show do
    link_to('History', history_backend_user_path(user), method: :get)
  end

  sidebar :versionate, :partial => "layouts/version", :only => :show

  member_action :history do
    @user = User.find(params[:id])
    @versions = @user.versions.reorder(created_at: :desc)
    render "layouts/history"
  end
end

我必须为每个模型 重复这行，我想知道如何才能把它擦干。

Answer 1

我最终得到了以下解决方案正在运行(另请注意，对User 资源的所有引用都已被概括):

# app/admin-shared/active_admin_loggable.rb

module ActiveAdminLoggable
  def self.extended(base)
    base.instance_eval do
      action_item :history, only: :show do
        link_to('History',
                eval("history_backend_#{resource.class.to_s.downcase}_path(#{resource.class.to_s.downcase})"),
                method: :get
        )
      end

      sidebar :versionate, :partial => "layouts/version", :only => :show

      member_action :history do
        @this_resource = eval("resource.class").find(params[:id])
        @versions = @this_resource.versions.reorder(created_at: :desc)
        render "layouts/history"
      end
    end
  end
end

和:

# app/admin/user.rb
ActiveAdmin.register User do
  extend ActiveAdminLoggable
  ...
end