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R bootstrap 按组加权平均值与数据表

转载 作者:行者123 更新时间:2023-12-04 16:05:39 25 4
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我正在尝试结合两种方法:

  1. Bootstrapping multiple columns in data.table in a scalable fashion

  1. Bootstrap weighted mean in R

这是一些随机数据:

## Generate sample data

# Function to randomly generate weights
set.seed(7)
rtnorm <- function(n, mean, sd, a = -Inf, b = Inf){
qnorm(runif(n, pnorm(a, mean, sd), pnorm(b, mean, sd)), mean, sd)
}

# Generate variables
nps <- round(runif(3500, min=-1, max=1), 0) # nps value which takes 1, 0 or -1
group <- sample(letters[1:11], 3500, TRUE) # groups
weight <- rtnorm(n=3500, mean=1, sd=1, a=0.04, b=16) # weights between 0.04 and 16

# Build data frame
df = data.frame(group, nps, weight)

# The following packages / libraries are required:
require("data.table")
require("boot")

这是上面第一篇博文中对加权均值进行自举的代码:

samplewmean <- function(d, i, j) {
d <- d[i, ]
w <- j[i, ]
return(weighted.mean(d, w))
}

results_qsec <- boot(data= df[, 2, drop = FALSE],
statistic = samplewmean,
R=10000,
j = df[, 3 , drop = FALSE])

这完全没问题。

下面是上面第二篇文章中的代码,在数据表中按组引导平均值:

dt = data.table(df)
stat <- function(x, i) {x[i, (m=mean(nps))]}
dt[, list(list(boot(.SD, stat, R = 100))), by = group]$V1

这也很好用。

我无法结合这两种方法:

正在运行......

dt[, list(list(boot(.SD, samplewmean, R = 5000, j = dt[, 3 , drop = FALSE]))), by = group]$V1

... 显示错误信息:

Error in weighted.mean.default(d, w) : 
'x' and 'w' must have the same length

正在运行......

dt[, list(list(boot(dt[, 2 , drop = FALSE], samplewmean, R = 5000, j = dt[, 3 , drop = FALSE]))), by = group]$V1

... 出现不同的错误:

Error in weighted.mean.default(d, w) : 
(list) object cannot be coerced to type 'double'

我仍然无法理解 data.table 中的参数以及如何组合运行 data.table 的函数。

如有任何帮助,我将不胜感激。

最佳答案

它与data.table 在函数范围内的行为有关。 d 仍然是 samplewmean 中的 data.table,即使在使用 i 进行子集化之后也是如此,而 weighted.mean 需要数值向量权重和值。如果您在调用 weighted.mean 之前unlist,您将能够修复此错误

Error in weighted.mean.default(d, w) : (list) object cannot be coerced to type 'double'

在传递给 weighted.mean 之前取消列出的代码:

samplewmean <- function(d, i, j) {
d <- d[i, ]
w <- j[i, ]
return(weighted.mean(unlist(d), unlist(w)))
}

dt[, list(list(boot(dt[, 2 , drop = FALSE], samplewmean, R = 5000, j = dt[, 3 , drop = FALSE]))), by = group]$V1

更像data.table(data.table 版本>= v1.10.2)的语法大概如下:

#a variable named original is being passed in from somewhere and i am unable to figure out from where
samplewmean <- function(d, valCol, wgtCol, original) {
weighted.mean(unlist(d[, ..valCol]), unlist(d[, ..wgtCol]))
}

dt[, list(list(boot(.SD, statistic=samplewmean, R=1, valCol="nps", wgtCol="weight"))), by=group]$V1

或者另一种可能的语法是:(参见 data.table faq 1.6 )

samplewmean <- function(d, valCol, wgtCol, original) {
weighted.mean(unlist(d[, eval(substitute(valCol))]), unlist(d[, eval(substitute(wgtCol))]))
}

dt[, list(list(boot(.SD, statistic=samplewmean, R=1, valCol=nps, wgtCol=weight))), by=group]$V1

关于R bootstrap 按组加权平均值与数据表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48886326/

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