javascript - 如何根据相似度更改数组中对象的参数？

Question

我有这个对象数组:

const data = [
  { position: 1, name: "a", score: 9000 },
  { position: 2, name: "b", score: 8000 },
  { position: 3, name: "c", score: 6000 },
  { position: 3, name: "c", score: 6000 },
  { position: 4, name: "d", score: 6000 },
  { position: 5, name: "e", score: 6000 },
  { position: 6, name: "f", score: 6000 },
  { position: 7, name: "g", score: 4000 },
  { position: 8, name: "h", score: 3000 },
  { position: 9, name: "i", score: 2500 },
  { position: 10, name: "j", score: 2500 },
  { position: 11, name: "k", score: 1000 },
  { position: 12, name: "l", score: 1000 },
];

我正在尝试仅使用简单的 JavaScript 对其进行迭代以获得以下结果:

const data = [
  { position: "1", name: "a", score: 9000 },
  { position: "2", name: "b", score: 8000 },
  { position: "3-6", name: "c", score: 6000 },
  { position: "3-6", name: "c", score: 6000 },
  { position: "3-6", name: "d", score: 6000 },
  { position: "3-6", name: "e", score: 6000 },
  { position: "3-6", name: "f", score: 6000 },
  { position: "7", name: "g", score: 4000 },
  { position: "8", name: "h", score: 3000 },
  { position: "9-10", name: "i", score: 2500 },
  { position: "9-10", name: "j", score: 2500 },
  { position: "11-12", name: "k", score: 1000 },
  { position: "11-12", name: "l", score: 1000 },
];

不幸的是，我尝试了很多不同的方法，但没有任何效果。任何提示如何实现这一目标？提前致谢。

这可能是我得到的最接近的:

function placement() {
  let repeat=0;
  for (let i = 0; i < data.length; i++) {
    let counter = 0;
    for (let j = 0; j < data.length; j++) {
      if (data[i].score == data[j].score) {
        if(data[i].position==data[j].position){
          repeat++;
        }
        counter++;
      }
    }
    if (counter > 1) {
      let k;
      let start=data[i].position;
      for (k = i; k < i + counter-1; k++) {
        data[k].position =
          start + "-" + data[i + counter-1].position;
      }
      i=k;
    }
  }
}

Answer 1

您可以先按score分组，然后为每个组添加位置。

const
    data = [{ position: 1, name: "a", score: 9000 }, { position: 2, name: "b", score: 8000 }, { position: 3, name: "c", score: 6000 }, { position: 3, name: "c", score: 6000 }, { position: 4, name: "d", score: 6000 }, { position: 5, name: "e", score: 6000 }, { position: 6, name: "f", score: 6000 }, { position: 7, name: "g", score: 4000 }, { position: 8, name: "h", score: 3000 }, { position: 9, name: "i", score: 2500 }, { position: 10, name: "j", score: 2500 }, { position: 11, name: "k", score: 1000 }, { position: 12, name: "l", score: 1000 }],
    result = data
        .reduce((r, o, i, a) => {
            if (!i || a[i - 1].score !== o.score) r.push([]);
            r[r.length - 1].push(o);
            return r;
        }, [])
        .flatMap(a => a.map((o, i, b) => b.length === 1
            ? o
            : { ...o, position: `${b[0].position}-${b[b.length - 1].position}` }
        ));

console.log(result);

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