php - 从具有特定内容(特殊字符)的数组中删除元素

Question

请求您帮助删除空数组元素，我尝试了 array_filter 和 array_map('array_filter', $array) 但似乎没有按预期工作。下面是数组结构和预期的输出，

原始数组

Array
(
    [0] => [
    [1] =>     [
    [2] =>         [
    [3] =>             "Test",
    [4] =>             "Server1",
    [5] =>             null,
    [6] =>             "Server2",
    [7] =>             null,
    [8] =>             "",
    [9] =>             "stopped",
    [10] =>         ]
    [11] =>     ]
    [12] => ]
)

预期的数组输出

Array
(
    [0] =>             "Test",
    [1] =>             "Server1",
    [2] =>             null,
    [3] =>             "Server2",
    [4] =>             null,
    [5] =>             "",
    [6] =>             "stopped",
)

请注意，不应删除 null 和 "" 元素。

Answer 1

您可以使用 preg_match()检查 [ 或 ] 上每个元素是否存在的函数:

preg_match ('/[\[\]]+/', $val, $matches);

如果有 - 跳过这个值。因此，如果您的输入数组具有如下结构:

$ar = Array
(
    0 => "[",
    1 => "    [",
    2 => "       [",
    3 =>             "Test",
    4 =>             "Server1",
    5 =>             null,
    6 =>             "Server2",
    7 =>             null,
    8 =>             "",
    9 =>             "stopped",
    10 =>  "       ]",
    11 =>  "   ]",
    12 => "]",
);

此函数将删除相应的元素:

function cleanArray($ar){ 
    $res = [];
    foreach($ar as $val){ 
        preg_match ('/[\[\]]+/', $val, $matches); 
        if(count($matches) == 0) $res[] = $val;
    }
    return $res;
}

Demo