wcf - 使用Azure时如何解决此错误 "AddressAccessDeniedException"？

Question

我有一个托管在 ASP.NET Web 应用程序中的 WCF 服务，在 Azure 中作为应用服务运行。

当我在本地计算机上运行此项目时没有错误。但是当部署到Azure时，出现以下错误:

[AddressAccessDeniedException: HTTP could not register URL http://+:80/docs/. Your process does not have access rights to this namespace (see http://go.microsoft.com/fwlink/?LinkId=70353 for details).]

有很多关于本地计算机的此错误的帖子，但与 azure 无关。 Theu 建议运行 netsh 来授予 url 权限，但我不知道如何在 Azure 中执行此操作。

事实上我正在尝试使用Swagger进行WCF实现，并且错误发生在这段代码中:

Global.asax.cs:

void Application_Start(object sender, EventArgs e)
{
    // Swagger
    RouteTable.Routes.Add(new ServiceRoute("api-docs", new WebServiceHostFactory(), typeof(SwaggerWcfEndpoint)));
    var swaggerHost = new WebServiceHost(typeof(SwaggerWcfEndpoint));
    swaggerHost.Open();
  }

Web.config:

<services>
  <service name="SwaggerWcf.SwaggerWcfEndpoint">
    <endpoint address="http://totvsrmwebapp.azurewebsites.net/docs" binding="webHttpBinding" contract="SwaggerWcf.ISwaggerWcfEndpoint" />
  </service>
</services>

这是堆栈跟踪:

'[HttpListenerException (0x5): Access is denied]
   System.Net.HttpListener.SetupV2Config() +333
   System.Net.HttpListener.Start() +297
   System.ServiceModel.Channels.SharedHttpTransportManager.OnOpen() +651

[AddressAccessDeniedException: HTTP could not register URL http://+:80/docs/. Your process does not have access rights to this namespace (see http://go.microsoft.com/fwlink/?LinkId=70353 for details).]
   System.ServiceModel.Channels.SharedHttpTransportManager.OnOpen() +1473
   System.ServiceModel.Channels.TransportManager.Open(TransportChannelListener channelListener) +296
   System.ServiceModel.Channels.TransportManagerContainer.Open(SelectTransportManagersCallback selectTransportManagerCallback) +122
   System.ServiceModel.Channels.TransportChannelListener.OnOpen(TimeSpan timeout) +64
   System.ServiceModel.Channels.HttpChannelListener`1.OnOpen(TimeSpan timeout) +67
   System.ServiceModel.Channels.CommunicationObject.Open(TimeSpan timeout) +308
   System.ServiceModel.Dispatcher.ChannelDispatcher.OnOpen(TimeSpan timeout) +61
   System.ServiceModel.Channels.CommunicationObject.Open(TimeSpan timeout) +308
   System.ServiceModel.ServiceHostBase.OnOpen(TimeSpan timeout) +136
   System.ServiceModel.Channels.CommunicationObject.Open(TimeSpan timeout) +308
   RMWCFWebApp.Global.Application_Start(Object sender, EventArgs e) +236

[HttpException (0x80004005): HTTP could not register URL http://+:80/docs/. Your process does not have access rights to this namespace (see http://go.microsoft.com/fwlink/?LinkId=70353 for details).]
   System.Web.HttpApplicationFactory.EnsureAppStartCalledForIntegratedMode(HttpContext context, HttpApplication app) +9982013
   System.Web.HttpApplication.RegisterEventSubscriptionsWithIIS(IntPtr appContext, HttpContext context, MethodInfo[] handlers) +118
   System.Web.HttpApplication.InitSpecial(HttpApplicationState state, MethodInfo[] handlers, IntPtr appContext, HttpContext context) +172
   System.Web.HttpApplicationFactory.GetSpecialApplicationInstance(IntPtr appContext, HttpContext context) +336
   System.Web.Hosting.PipelineRuntime.InitializeApplication(IntPtr appContext) +296

[HttpException (0x80004005): HTTP could not register URL http://+:80/docs/. Your process does not have access rights to this namespace (see http://go.microsoft.com/fwlink/?LinkId=70353 for details).]
   System.Web.HttpRuntime.FirstRequestInit(HttpContext context) +9963380
   System.Web.HttpRuntime.EnsureFirstRequestInit(HttpContext context) +101
   System.Web.HttpRuntime.ProcessRequestNotificationPrivate(IIS7WorkerRequest wr, HttpContext context) +254'

Answer 1

我已经重现了您的问题。根据我的经验，Azure Web应用程序不允许我们注册url“http://totvsrmwebapp.azurewebsites.net/docs”。如果你想这样做，我建议你使用Azure云服务，并在启动任务中执行命令(netsh http add urlacl url=)。更多云服务信息请引用this article 。看看this article了解如何使用启动任务。