php - 在 PHP 中将 2 个日期之间的天分组为月

Question

假设我们有:

$startDt="10/28/2017";
$endDt="12/2/2017";

我想要将这些日期之间的几天分组为几个月。输出必须类似于:

[
   "October"=>[28, 29, 30, 31],
   "November"=>[1, ..., 30],
   "December"=>[1,2]
]

不知道如何实现它。有什么建议吗？

Answer 1

您可以使用PHP的内置类DateTime , DateInterval和 DatePeriod为了这;例如:

<?php 

$start = new DateTime('10/28/2017');    
$end = new DateTime('12/2/2017');
$interval = new DateInterval('P1D'); // 1 day

$period = new DatePeriod($start, $interval, $end);

$days = [];  

foreach ($period as $dt) {
  $month = $dt->format('F');
  $day = $dt->format('j');
  $days[$month][] = $day;
} 

print_r($days);

Here is the documentation about date formatting

请注意，如果时间相同，DatePeriod 会上升到但排除最后一个日期(这里就是这种情况，因此您可能想要修改结束日期为了解决这个问题 - 添加第二个应该可以解决问题；例如:

$end = new DateTime('12/2/2017');
$end->modify('+1 second');
// or $end->setTime(0, 0, 1); H/T to @ishegg

$period = new DatePeriod($start, $interval, $end);
// etc.

这会产生:

Array
(
    [October] => Array
        (
            [0] => 28
            [1] => 29
            [2] => 30
            [3] => 31
        )

    [November] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 3
            [3] => 4
            [4] => 5
            [5] => 6
            [6] => 7
            [7] => 8
            [8] => 9
            [9] => 10
            [10] => 11
            [11] => 12
            [12] => 13
            [13] => 14
            [14] => 15
            [15] => 16
            [16] => 17
            [17] => 18
            [18] => 19
            [19] => 20
            [20] => 21
            [21] => 22
            [22] => 23
            [23] => 24
            [24] => 25
            [25] => 26
            [26] => 27
            [27] => 28
            [28] => 29
            [29] => 30
        )

    [December] => Array
        (
            [0] => 1
        )

)

希望这有帮助:)