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带分页的 Django 过滤器

转载 作者:行者123 更新时间:2023-12-04 15:50:47 26 4
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我正在尝试按照以下教程使用 django 过滤器进行分页,但该教程似乎缺少某些内容,而且我无法使用基于函数的 View 方法显示分页。

https://simpleisbetterthancomplex.com/tutorial/2016/08/03/how-to-paginate-with-django.html

My updated users_list.html is the following:

{% extends 'base.html' %}

{% load widget_tweaks %}

{% block content %}
<form method="get">
<div class="well">
<h4 style="margin-top: 0">Filter</h4>
<div class="row">
<div class="form-group col-sm-4 col-md-4">
<label/> 3-4 User ID
{% render_field filter.form.employeentname class="form-control" %}
</div>
<div class="form-group col-sm-4 col-md-4">
<label/> First Name
{% render_field filter.form.employeefirstname class="form-control" %}
</div>
<div class="form-group col-sm-4 col-md-4">
<label/> Last Name
{% render_field filter.form.employeelastname class="form-control" %}
</div>

<div class="form-group col-sm-4 col-md-4">
<label/> Status
{% render_field filter.form.statusid class="form-control" %}
</div>

<div class="form-group col-sm-4 col-md-4">
<label/> Title
{% render_field filter.form.positiondesc class="form-control" %}
</div>
</div>
<button type="submit" class="btn btn-primary">
<span class="glyphicon glyphicon-search"></span> Search
</button>
</div>
</form>
<form action = "{% url 'results' %}" form method = "POST">
{% csrf_token %}
<table class="table table-bordered">
{{ form.as_table }}
<thead>
<tr>
<th>3-4</th>
<th>First name</th>
<th>Last name</th>
<th>Title</th>
<th>Status</th>
<th></th>

</tr>
</thead>
<tbody>
{% for user in filter.qs %}
<tr>
<td>{{ user.employeentname }}</td>
<td>{{ user.employeefirstname }}</td>
<td>{{ user.employeelastname }}</td>
<td>{{ user.positiondesc }}</td>
<td>{{ user.statusid }}</td>
<td><input type="checkbox" name="usercheck" value = "{{user.employeentname}}" />&nbsp;</td>

</tr>
{% empty %}
<tr>
<td colspan="5">No data</td>
</tr>
{% endfor %}
</tbody>
</table>



<button class="btn btn-primary" type="submit">Select User</button>
</form>
{% endblock %}

我下面的观点基于教程,但我使用的是我自己的模型:
def user_list(request):
user_list = Employee.objects.all()
user_filter = UserFilter(request.GET, queryset=user_list)
user_list = user_filter.qs
page = request.GET.get('page', 1)



paginator = Paginator(user_list.qs, 10)
try:
users = paginator.page(page)
except PageNotAnInteger:
users = paginator.page(1)
except EmptyPage:
users = paginator.page(paginator.num_pages)


args = {'filter':user_filter, 'users':users}


return render(request, 'user_list.html', args)

我的目录结构设置如下,也许是这样的:

enter image description here
from django import forms
from .models import Employee

import django_filters


class UserFilter(django_filters.FilterSet):


class Meta:
model = Employee
fields = ['employeentname', 'employeefirstname', 'employeelastname', 'statusid', 'positiondesc']





def __init__(self, *args, **kwargs):
super(UserFilter, self).__init__(*args, **kwargs)
# at sturtup user doen't push Submit button, and QueryDict (in data) is empty
if self.data == {}:
self.queryset = self.queryset.none()

在那里移动分页后添加了我的 base.html:
{% load static %}<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link href="{% static 'css/bootstrap.min.css' %}" rel="stylesheet">
<!--[if lt IE 9]>
<script src="https://oss.maxcdn.com/html5shiv/3.7.3/html5shiv.min.js"></script>
<script src="https://oss.maxcdn.com/respond/1.4.2/respond.min.js"></script>
<![endif]-->
<style type="text/css">
.page-header {
margin-top: 0;
}
</style>
</head>
<body>
{% include 'includes/header.html' %}
<div class="container">
{% block content %}
{% if users.has_other_pages %}
<ul class="pagination">
{% if users.has_previous %}
<li><a href="?page={{ users.previous_page_number }}">&laquo;</a></li>
{% else %}
<li class="disabled"><span>&laquo;</span></li>
{% endif %}
{% for i in users.paginator.page_range %}
{% if users.number == i %}
<li class="active"><span>{{ i }} <span class="sr-only">(current)
</span></span></li>
{% else %}
<li><a href="?page={{ i }}">{{ i }}</a></li>
{% endif %}
{% endfor %}
{% if users.has_next %}
<li><a href="?page={{ users.next_page_number }}">&raquo;</a></li>
{% else %}
<li class="disabled"><span>&raquo;</span></li>
{% endif %}
</ul>
{% endif %}
{% endblock %}
</div>
<script src="{% static 'js/jquery-3.1.1.min.js' %}"></script>
<script src="{% static 'js/bootstrap.min.js' %}"></script>





{% block javascript %}

{% endblock %}
</body>
</html>

我期望我的过滤器为每 10 个用户对搜索结果进行分页。我现在得到的是整个用户集。过滤器工作正常,但不是分页。

最佳答案

你可以这样分页:
注意:user_filter.qs 有过滤结果,user_filter.queryset 有未过滤结果
View .py

      def search(request):
user_list = Employee.objects.all()
user_filter = UserFilter(request.GET, queryset=user_list)
user_list = user_filter.qs

paginator = Paginator(user_list, 10)
page = request.GET.get('page', 1)
try:
users = paginator.page(page)
except PageNotAnInteger:
users = paginator.page(1)
except EmptyPage:
users = paginator.page(paginator.num_pages)
args = {'paginator': paginator,'filter':user_filter,
'users':users,}
return render(request, 'search/user_list.html', args)
然后在模板中:
   {% for user in users %}
<tr>
<td>{{ user.employeeusername }}</td>
<td>{{ user.employeefirstname }}</td>
<td>{{ user.employeelastname }}</td>
<td>{{ user.statusid }}</td>
<td><input type="checkbox" name="usercheck" />&nbsp;</td>

</tr>
{% empty %}
<tr>
<td colspan="5">No data</td>
</tr>
{% endfor %}
</tbody>
 {% if users.has_other_pages %}
<ul class="pagination">
{% if users.has_previous %}
<li><a href="?page={{ users.previous_page_number }}">&laquo;</a></li>
{% else %}
<li class="disabled"><span>&laquo;</span></li>
{% endif %}
{% for i in users.paginator.page_range %}
{% if users.number == i %}
<li class="active"><span>{{ i }} <span class="sr-only">(current)
</span></span></li>
{% else %}
<li><a href="?page={{ i }}">{{ i }}</a></li>
{% endif %}
{% endfor %}
{% if users.has_next %}
<li><a href="?page={{ users.next_page_number }}">&raquo;</a></li>
{% else %}
<li class="disabled"><span>&raquo;</span></li>
{% endif %}
</ul>
{% endif %}

关于带分页的 Django 过滤器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48546864/

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