scala - 流程组成和异常

Question

如何从与#&& 等结合的外部进程中捕获异常？

scala> import scala.sys.process._     
scala> try{ "throw " ! }catch{ case e: Exception => }
res1: AnyVal = ()
scala> try{ "throw " #&& "ls" ! }catch{ case e: Exception => }
Exception in thread "Thread-10" java.io.IOException: Cannot run program "throw": error=2, No such file or directory

Answer 1

你已经这样做了。尝试

try {
 val x = "throw" #&& "ls" !
} catch {
 case x => println("caught")
}

!只是将异常记录到控制台，当您在 REPL 中看到它时会有点困惑，但它不会崩溃。