python - 有没有办法让列表包含所有索引

Question

我一直在尝试制作一个列表，其中包含 known_in_lines list 中单词的所有常见可能性。然而，问题是，因为我正在使用“for 循环”，每次“i”上升一个，列表将重置，因此代码将以小写字母打印列表的最后一个索引而告终。 .有没有一种方法可以将列表的所有索引都放入函数中并一起返回？基本上，我能否在函数外部创建 insensitive_string 列表，这样它就不会在我每次使用该函数时都重置列表？

def case_insensitive(*texts) :
    insensitive_string = []
    for text in texts :
        insensitive_string.extend [text.lower(),text.upper(),text.capitalize()]
    return (insensitive_string)

known_in_lines = ["hello" ,
                 "hi" ,
                 "what's up" ,
                 "how are you doing" ,
                 "how was your day" ]

for i in range (0,len(known_in_lines)) :
    insensitive_string = case_insensitive(known_in_lines[i])

print (insensitive_string)

Answer 1

您可以在循环内扩展列表，但事实上，如果您给它很多参数，这正是 case_insensitive 函数所做的。只是做:

insensitive_string = case_insensitive(*known_in_lines)

您将获得:

['hello', 'HELLO', 'Hello', 'hi', 'HI', 'Hi', "what's up", "WHAT'S UP", "What's up", 'how are you doing', 'HOW ARE YOU DOING', 'How are you doing', 'how was your day', 'HOW WAS YOUR DAY', 'How was your day']