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r - ntile 函数在最新版本的 R 中不起作用

转载 作者:行者123 更新时间:2023-12-04 15:23:26 25 4
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我的数据是

my_basket <- data.frame(ITEM_GROUP = c("Fruit","Fruit","Fruit","Fruit","Fruit","Vegetable","Vegetable","Vegetable","Vegetable","Dairy","Dairy","Dairy","Dairy","Dairy"), 
ITEM_NAME = c("Apple","Banana","Orange","Mango","Papaya","Carrot","Potato","Brinjal","Raddish","Milk","Curd","Cheese","Milk","Paneer"),
Price = c(100,80,80,90,65,70,60,70,25,60,40,35,50,120))

我想使用 ntile 函数计算百分位数列

df1 = mutate(my_basket, percentile_rank = ntile(my_basket$Price,100))

它应该给我一个看起来像 correct_df 的数据框

correct_df<- data.frame(ITEM_GROUP = c("Fruit","Fruit","Fruit","Fruit","Fruit","Vegetable","Vegetable","Vegetable","Vegetable","Dairy","Dairy","Dairy","Dairy","Dairy"), 
ITEM_NAME = c("Apple","Banana","Orange","Mango","Papaya","Carrot","Potato","Brinjal","Raddish","Milk","Curd","Cheese","Milk","Paneer"),
Price = c(100,80,80,90,65,70,60,70,25,60,40,35,50,120),
percentile_rank=c(86,65,72,79,43,51,29,58,1,36,15,8,22,93))

但是我得到了一个看起来像 wrong_df 的数据框

wrong_df<- data.frame(ITEM_GROUP = c("Fruit","Fruit","Fruit","Fruit","Fruit","Vegetable","Vegetable","Vegetable","Vegetable","Dairy","Dairy","Dairy","Dairy","Dairy"), 
ITEM_NAME = c("Apple","Banana","Orange","Mango","Papaya","Carrot","Potato","Brinjal","Raddish","Milk","Curd","Cheese","Milk","Paneer"),
Price = c(100,80,80,90,65,70,60,70,25,60,40,35,50,120),
percentile_rank=c(13,10,11,12,7,8,5,9,1,6,3,3,4,14))

自从我将 R 版本更新到 4.0.2 后才出现这个问题

最佳答案

我认为这不是 R 问题,但似乎是 dplyr 1.0.0 的问题,如 this open GitHub issue 中所述.查看从那里获取的两个函数的输出差异。

ntile_083(my_basket$Price,100)
#[1] 86 65 72 79 43 51 29 58 1 36 15 8 22 93
ntile_100(my_basket$Price,100)
#[1] 13 10 11 12 7 8 5 9 1 6 3 2 4 14

您现在可以使用 ntile_083 获得以前的功能。

关于r - ntile 函数在最新版本的 R 中不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62829568/

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