amazon-ec2 - 用于 EC2 Image Builder 的 yaml 中的多行 bash 脚本

Question

我正在尝试创建自定义组件文档。虽然我已经使用各种 yaml linters 测试了 yaml 文件，但 EC2 Image builder 提示以下错误

Failed to create component. Fix the error(s) and try again:
The value supplied for parameter 'data' is not valid. Parsing step 'ConfigureMySQL' in phase 'build' failed. Error: line 4: cannot unmarshal map into string.

我无法弄清楚我的 yaml 文件有什么问题

name: MyJavaAppTestDocument
description: This is JavaApp Document
schemaVersion: 1.0

phases:
  - name: build
    steps:
      - name: InstallSoftware
        action: ExecuteBash
        inputs:
          commands:
            - sudo yum update -y
            - sudo yum install -y java-1.8.0
            - sudo amazon-linux-extras install -y tomcat8.5
            - sudo yum install -y https://dev.mysql.com/get/mysql57-community-release-el7-11.noarch.rpm
            - sudo yum install -y mysql-community-server
      
      - name: ConfigureTomcat
        action: ExecuteBash
        inputs:
          commands:
            - sudo sed -i 's/<\/tomcat-users>/\n<role rolename="manager-gui"\/>\n  <role 
              rolename="manager-script"\/>\n  <role rolename="admin-gui"\/>\n  <user username="admin" 
              password="admin" roles="manager-gui,manager-script,admin-gui"\/>\n<\/tomcat-users>/' 
              /etc/tomcat/tomcat-users.xml
            - sudo systemctl start tomcat
            - sudo systemctl enable tomcat
      
      - name: ConfigureMySQL
        action: ExecuteBash
        inputs:
          commands:
            - sudo systemctl start mysqld
            - sudo systemctl enable mysqld
            - mysqlpass=$(sudo grep 'temporary password' /var/log/mysqld.log | sed 's/.*root@localhost: //')
            - mysql -u root -p$mysqlpass --connect-expired-password -h localhost -e "ALTER USER 'root'@'localhost' IDENTIFIED BY 'whyDoTh1s@2020'"
            - |
              sudo cat <<EoF > /tmp/mysql-create-user.sql
              CREATE USER 'admin'@'%' IDENTIFIED BY 'whyDoTh1s@2020';
              GRANT ALL PRIVILEGES ON *.* TO 'admin'@'%' WITH GRANT OPTION;
              EoF

            - sudo mysql -u root -pwhyDoTh1s@2020 -h localhost < /tmp/mysql-create-user.sql

感谢有人能帮我找到错误。目标是使用预配置的软件和设置构建 AMI。

Answer 1

由于 :，您收到该错误在这一行:

- mysqlpass=$(sudo grep 'temporary password' /var/log/mysqld.log | sed 's/.*root@localhost: //')

YAML 解析器将该行解释为创建映射，而不是在现有映射中创建字符串条目。我能够在我自己的 YAML 中使用的解决方法是包围 :用单引号，所以问题行会变成

- mysqlpass=$(sudo grep 'temporary password' /var/log/mysqld.log | sed 's/.*root@localhost':' //')

据本人使用和 this online YAML parser我使用该解决方案进行了测试，应该可以解决问题。