graphviz - 如何在Graphviz Dot中创建从节点到子图的边？

Question

我想创建一个看起来像这样的图形，i。 e.从节点 Manufacturer of means of production 开始的边在哪里到同名的子图。



我为此编写了以下代码:

digraph G {
    rankdir=LR;
    compound=true;

    graph [fontname="Liberation Mono"];
    node [fontname="Liberation Mono"];
    edge [fontname="Liberation Mono"];

    subgraph cluster0 {
        label="System components";
        mmp [label="Manufacturer of means of production", shape=box];
    }

    subgraph cluster1 {
        t1start [label="Start of tact 1", shape=point]
        t1end [label="End of tact 1", shape=point ]
        subgraph cluster1_mmp {
            label="Manufacturer of means of production"

            cluster1_1 [label="Node 1", color=white]


            subgraph cluster1_1_1 {
                label="Technological cycle 1"

                cluster1_1_1 [label="Node 2", color=white]
            }
            subgraph cluster1_1_2 {
                label="Technological cycle 2"

                cluster1_1_2 [label="Node 2", color=white]
            }
        }
    }

    subgraph cluster2 {
        label="Такт 2"
        t2start [label="Start of tact 2", shape=point]
        t2end [label="End of tact 2", shape=point]

    }
    t1end -> t2start
    mmp -> cluster1_1 [ltail=cluster1_mmp]; 
}

如果我尝试编译此代码 ( "C:\Program Files (x86)\Graphviz2.38\bin\"dot.exe -Tpng -ograph.png graph.dot )，则会收到警告 Warning: mmp -> cluster1_1: tail not inside tail cluster cluster1_mmp .

如何修复它并使边缘进入子图？

更新 1:

您可以在下面找到预期结果的图像 - 从节点到子图(子图，而不是子图中的节点)的边。这个边缘在下图中是红色的。



更新 2 : 更改了如下所示的代码。

digraph G {
    rankdir=LR;
    compound=true;

    graph [fontname="Liberation Mono"];
    node [fontname="Liberation Mono"];
    edge [fontname="Liberation Mono"];

    subgraph cluster0 {
        label="System components";
        mmp [label="Manufacturer of means of production", shape=box];
    }

    subgraph cluster1 {
        t1start [label="Start of tact 1", shape=point]
        t1end [label="End of tact 1", shape=point ]
        subgraph cluster1_mmp {
            label="Manufacturer of means of production"

            testNode [label="Node 1", color=white]

            subgraph cluster1_1_1 {
                label="Technological cycle 1"

                cluster1_1_1 [label="Node 2", color=white]
            }
            subgraph cluster1_1_2 {
                label="Technological cycle 2"

                cluster1_1_2 [label="Node 2", color=white]
            }
        }
    }

    subgraph cluster2 {
        label="Такт 2"
        t2start [label="Start of tact 2", shape=point]
        t2end [label="End of tact 2", shape=point]

    }
    t1end -> t2start
    mmp -> cluster1 [ltail=cluster0, lhead=cluster1, label="           "];

}

Answer 1

你需要改变你的最后一行

mmp -> cluster1_1 [ltail=cluster1_mmp];

到

mmp -> cluster1_1 [lhead=cluster1 label="           "]

然后图表按预期出现



此外，如果您希望边缘从框外开始，那么您会这样做

mmp -> cluster1_1 [ltail=cluster0 lhead=cluster1 label="           "];

编辑

最终使用的代码

digraph G {
    rankdir=LR;
    compound=true;

    graph [fontname="Liberation Mono"];
    node [fontname="Liberation Mono"];
    edge [fontname="Liberation Mono"];

    subgraph cluster0 {
        label="System components";
        mmp [label="Manufacturer of means of production", shape=box];
    }

    subgraph cluster1 {
        t1start [label="Start of tact 1", shape=point]
        t1end [label="End of tact 1", shape=point ]
        subgraph cluster1_mmp {
            label="Manufacturer of means of production"

            cluster1_1 [label="Node 1", color=white]


            subgraph cluster1_1_1 {
                label="Technological cycle 1"

                cluster1_1_1 [label="Node 2", color=white]
            }
            subgraph cluster1_1_2 {
                label="Technological cycle 2"

                cluster1_1_2 [label="Node 2", color=white]
            }
        }
    }

    subgraph cluster2 {
        label="Такт 2"
        t2start [label="Start of tact 2", shape=point]
        t2end [label="End of tact 2", shape=point]

    }
    t1end -> t2start
    mmp -> cluster1_1 [lhead=cluster1 label="           "]
}

fiddle link对于相同的