python - 如何在 View 中捕获 django.http.request.DisallowedHost？

Question

这个有效:

def index(request):

    try:
        # Do some stuff

    except:
        return render(request, 'something.html')

但是我怎样才能捕捉到错误:django.http.request.DisallowedHost？

试过了，还是不行:

from django.core.exceptions import DisallowedHost

def index(request):

    try:
        # Do some stuff

    except DisallowedHost:
        return render(request, 'something.html')

Answer 1

请不要更换中间件或做一些其他奇怪的事情。这非常简单:DisallowedHost() 由在请求对象上调用 get_host() 的第一件事引发。通常，这是一个中间件，因为在请求/响应周期中过早地执行它会导致无法关闭或自定义。

因此首先在链中注入(inject)您的自定义中间件并在那里短路:

# File: main.middleware
from django.shortcuts import redirect
from django.core.exceptions import DisallowedHost


class FriendlyDisallowedHost:
    def __init__(self, get_response):
        self.get_response = get_response

    def __call__(self, request, *args, **kwargs):
        try:
            checkhost = request.get_host()
        except DisallowedHost:
            return redirect("http://localhost/")
        
        return self.get_response(request)

设置:

MIDDLEWARE = [
    "main.middleware.FriendlyDisallowedHost",
    # ... rest of middleware
]