php - PHP中的preg_replace按组

Question

我有一个字符串

$cmd = "java -jar yuicompressor-2.4.8.jar --type *file_type* *original_file* > *new_file*";

我想像下面这样替换

java -jar yuicompressor-2.4.8.jar --type css css/style.css > css/style.min.css

我所做的是

$cmd = str_replace("*original_file*", $v, $cmd);
$cmd = str_replace("*new_file*", "$k", $cmd);
$cmd = str_replace("*file_type*", "css", $cmd);

我正在寻找一种类似 preg_replace 的排序方式。任何建议将不胜感激。

Answer 1

除了我的评论之外，您还可以使用以下正则表达式:

<?php
$cmd = "java -jar yuicompressor-2.4.8.jar --type *file_type* *original_file* > *new_file*";

$replacements = array(
    "file_type" => "something else",
    "original_file" => "original",
    "new_file" => "new");

$regex = '~\*([^*]+)\*~';
# look for a star literally
# capture everything that is not a star to group 1
# look for the closing star

$cmd = preg_replace_callback($regex,
    function($match) use($replacements) {
        return $replacements[$match[1]];
        # return the new value with match as key
    },
    $cmd);
echo $cmd;
// output: java -jar yuicompressor-2.4.8.jar --type something else original > new
?>