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javascript - 当在 ReactJs React-Redux 中仅创建或更新列表中的一个项目时,如何停止重新渲染整个项目列表?

转载 作者:行者123 更新时间:2023-12-04 15:10:55 25 4
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我正在制作这个 Web 应用程序,其中包含用户可以回答这些帖子的帖子。我使用 React-Redux 来管理应用程序的状态。每次我创建或更新特定帖子的答案时,属于该帖子的整个答案列表都会重新呈现,我想停止它并仅呈现新创建或更新的答案。我已经使用完全相同的方式发表评论,并且效果很好。评论不会被重新渲染,但答案会。我只是想不通这里有什么问题。请引用下面的代码。
我尝试使用 React.memo()而且它也不起作用!
回答渲染组件,

export function Answer() {
const classes = useStyles();
const dispatch = useDispatch();

const { postId } = useParams();

const postAnswers = useSelector(state => state.Answers);

const [answers, setAnswers] = React.useState(postAnswers.answers);

React.useEffect(() => {
if(postAnswers.status === 'idle') dispatch(fetchAnswers(postId));
}, [dispatch]);

React.useEffect(() => {
if(postAnswers.answers) handleAnswers(postAnswers.answers);
}, [postAnswers]);

const handleAnswers = (answers) => {
setAnswers(answers);
};

const AnswersList = answers ? answers.map(item => {

const displayContent = item.answerContent;

return(
<Grid item key={item.id}>
<Grid container direction="column">
<Grid item>
<Paper component="form" className={classes.root} elevation={0} variant="outlined" >
<div className={classes.input}>
<Typography>{displayContent}</Typography>
</div>
</Paper>
</Grid>
</Grid>
</Grid>
);
}): undefined;

return(
<Grid container direction="column" spacing={2}>
<Grid item>
<Divider/>
</Grid>
<Grid item>
<Grid container direction="column" alignItems="flex-start" justify="center" spacing={2}>
{AnswersList}
</Grid>
</Grid>
<Grid item>
<Divider/>
</Grid>
</Grid>
);
}
获取答案 redux 应用,
export const fetchAnswers = (postId) => (dispatch) => {
dispatch(answersLoading());

axios.get(baseUrl + `/answer_api/?postBelong=${postId}`)
.then(answers =>
dispatch(addAnswers(answers.data))
)
.catch(error => {
console.log(error);
dispatch(answersFailed(error));
});
}
发布答案,
export const postAnswer = (data) => (dispatch) => {
axios.post(baseUrl + `/answer_api/answer/create/`,
data
)
.then(response => {
console.log(response);
dispatch(fetchAnswers(postBelong)); //This is the way that I update answers state every time a new answer is created or updated
})
.catch(error => {
console.log(error);
});
}
任何帮助都会很棒。谢谢!

最佳答案

添加项目后,您从 api 获取所有项目,以便在状态中重新创建所有项目。如果您为容器组件提供项目的 id 并让选择器将项目作为 JSON 获取,然后解析回对象,您可以记住它并防止重新渲染,但我认为重新渲染可能更好。
以下是该项目的内存 JSON 示例:

const { Provider, useDispatch, useSelector } = ReactRedux;
const { createStore, applyMiddleware, compose } = Redux;
const { createSelector } = Reselect;
const fakeApi = (() => {
const id = ((num) => () => ++num)(1);
const items = [{ id: 1 }];
const addItem = () =>
Promise.resolve().then(() =>
items.push({
id: id(),
})
);
const updateFirst = () =>
Promise.resolve().then(() => {
items[0] = { ...items[0], updated: id() };
});
const getItems = () =>
//this is what getting all the items from api
// would do, it re creates all the items
Promise.resolve(JSON.parse(JSON.stringify(items)));
return {
addItem,
getItems,
updateFirst,
};
})();
const initialState = {
items: [],
};
//action types
const GET_ITEMS_SUCCESS = 'GET_ITEMS_SUCCESS';
//action creators
const getItemsSuccess = (items) => ({
type: GET_ITEMS_SUCCESS,
payload: items,
});
const getItems = () => (dispatch) =>
fakeApi
.getItems()
.then((items) => dispatch(getItemsSuccess(items)));
const update = () => (dispatch) =>
fakeApi.updateFirst().then(() => getItems()(dispatch));
const addItem = () => (dispatch) =>
fakeApi.addItem().then(() => getItems()(dispatch));
const reducer = (state, { type, payload }) => {
if (type === GET_ITEMS_SUCCESS) {
return { ...state, items: payload };
}
return state;
};
//selectors
const selectItems = (state) => state.items;
const selectItemById = createSelector(
[selectItems, (_, id) => id],
(items, id) => items.find((item) => item.id === id)
);
const createSelectItemAsJSON = (id) =>
createSelector(
[(state) => selectItemById(state, id)],
//return the item as primitive (string)
(item) => JSON.stringify(item)
);
const createSelectItemById = (id) =>
createSelector(
[createSelectItemAsJSON(id)],
//return the json item as object
(item) => JSON.parse(item)
);
//creating store with redux dev tools
const composeEnhancers =
window.__REDUX_DEVTOOLS_EXTENSION_COMPOSE__ || compose;
const store = createStore(
reducer,
initialState,
composeEnhancers(
applyMiddleware(
({ dispatch, getState }) => (next) => (action) =>
//simple thunk implementation
typeof action === 'function'
? action(dispatch, getState)
: next(action)
)
)
);
const Item = React.memo(function Item({ item }) {
const rendered = React.useRef(0);
rendered.current++;
return (
<li>
rendered:{rendered.current} times, item:{' '}
{JSON.stringify(item)}
</li>
);
});
const ItemContainer = ({ id }) => {
const selectItem = React.useMemo(
() => createSelectItemById(id),
[id]
);
const item = useSelector(selectItem);
return <Item item={item} />;
};
const ItemList = () => {
const items = useSelector(selectItems);
return (
<ul>
{items.map(({ id }) => (
<ItemContainer key={id} id={id} />
))}
</ul>
);
};
const App = () => {
const dispatch = useDispatch();
React.useEffect(() => dispatch(getItems()), [dispatch]);
return (
<div>
<button onClick={() => dispatch(addItem())}>
add item
</button>
<button onClick={() => dispatch(update())}>
update first item
</button>
<ItemList />
</div>
);
};

ReactDOM.render(
<Provider store={store}>
<App />
</Provider>,
document.getElementById('root')
);
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.8.4/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.8.4/umd/react-dom.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/redux/4.0.5/redux.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-redux/7.2.0/react-redux.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/reselect/4.0.0/reselect.min.js"></script>
<div id="root"></div>

关于javascript - 当在 ReactJs React-Redux 中仅创建或更新列表中的一个项目时,如何停止重新渲染整个项目列表?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/65216588/

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