spring - Thymeleaf 注册页面 - 执行处理器 'org.thymeleaf.spring4.processor.attr.SpringInputGeneralFieldAttrProcessor' 期间出错

Question

我正在为网站制作注册页面。我知道为了创建新用户，需要一个 id，所以我们有以下字段:

<input type="hidden" th:field="{*id} />

但是，当我转到该页面时，我收到了我在这篇文章标题中提到的错误。

这是有问题的表格:

<form th:action="@{/users/register}" th:object="${user}" class="form-signin" method="POST">
    <h2 class="form-signin-heading">Register</h2>
    <input type="hidden" th:field="*{id}" />
    <label for="inputUsername" class="sr-only">Username*</label>
    <input type="text" th:field="*{username}" name="username" id="inputUsername" class="form-control" placeholder="Username" required="required" autofocus="autofocus" />
    <label for="inputEmail" class="sr-only">Email Address*</label>
    <input type="text" th:field="*{email}" name="email" id="inputEmail" class="form-control" placeholder="Email address" required="required" autofocus="autofocus" />
    <label for="inputPassword" class="sr-only">Password</label>
    <input type="password" th:field="*{password}" name="password" id="inputPassword" class="form-control" placeholder="Password" required="required" />
    <label for="inputConfirmPassword" class="sr-only">Confirm Password</label>
    <input type="password" th:field="${confirmPassword}" name="confirmPassword" id="inputConfirmPassword" class="form-control" placeholder="Confirm password" required="required" />
    <button class="btn btn-lg btn-primary btn-block" type="submit">Register</button>
</form>

这是我的用户 Controller :

@RequestMapping("/register")
public String registerAction(Model model) {
    model.addAttribute("user", new User());
    model.addAttribute("confirmPassword", "");
    return "views/users/register";
}

@RequestMapping(value="/register", method = RequestMethod.POST)
public String doRegister(User user) {
    User savedUser = userService.save(user);
    return "redirect:/"; //redirect to homepage
}

以及 User 实体的第一部分:

@Entity
@Table(name = "users")
public class User {

// Default constructor require by JPA
public User() {}

@Column(name = "id")
@Id @GeneratedValue
private Long id;

public void setId(long id) {
    this.id = id;
}

public long getId() {
    return id;
}

据我所知，这里没有任何问题，所以我被卡住了。

我正在关注这个例子: https://github.com/cfaddict/spring-boot-intro

有任何想法吗？

Answer 1

问题是您声明 id 属性的方式。该字段使用为空的引用类型 Long。 getter 使用原始 long。当 Spring 访问 id 字段时，它会尝试将导致错误的空值拆箱。将您的域类更改为

@Entity
@Table(name = "users")
public class User {

    // Default constructor required by JPA
    public User() {}

    @Id
    @Column(name = "id")
    @GeneratedValue
    private Long id;

    public void setId(Long id) {
        this.id = id;
    }

    public Long getId() {
        return id;
    }
}