当搜索到的词在定义的表达式中时，python 绕过 re.finditer 匹配

Question

我有一个要在文本中查找的单词列表 (find_list) 和一个包含那些我想在文本中绕过的单词的表达式列表 (scape_list)。

我可以使用这段代码找到文本中的所有单词:

find_list = ['name', 'small']
scape_list = ['small software', 'company name']

text = "My name is Klaus and my middle name is Smith. I work for a small company. The company name is Small Software. Small Software sells Software Name."

final_list = []

for word in find_list:
    
    s = r'\W{}\W'.format(word)
    matches = re.finditer(s, text, (re.MULTILINE | re.IGNORECASE))

    for word_ in matches:
        final_list.append(word_.group(0))

最终名单是:

['name', 'name', 'name', 'Name.', 'small', 'Small', 'Small']

有没有办法绕过 scape_list 中列出的表达式并获得像这样的 final_list:

['name', 'name', 'name.', 'small']

final_list 和 scape_list 一直在更新。所以我认为正则表达式是一个很好的方法。

Answer 1

您可以使用正则表达式捕获 find_list 单词前后的单词，并检查这两个组合是否不存在于 scape_list 中。我在更改代码的地方添加了注释。 (最好将 scape_list 更改为 set，如果它将来会变大的话)

find_list = ['name', 'small']
scape_list = ['small software', 'company name']

text = "My name is Klaus and my middle name is Smith. I work for a small company. The company name is Small Software. Small Software sells Software Name."

final_list = []

for word in find_list:
    
    s = r'(\w*\W)({})(\W\w*)'.format(word) # change the regex to capture adjacent words
    matches = re.finditer(s, text, (re.MULTILINE | re.IGNORECASE))

    for word_ in matches:
        if ((word_.group(1) + word_.group(2)).strip().lower() not in scape_list
            and (word_.group(2) + word_.group(3)).strip().lower() not in scape_list): # added this condition
            final_list.append(word_.group(2)) # changed here

final_list
['name', 'name', 'Name', 'small']