ansible - 从列表中排除 AnsibleUndefined

Question

任务的相关部分:

- name: Get join-token for worker nodes
  set_fact:
    join_token_worker: "{{ ansible_play_hosts_all | map('extract', hostvars, ['result', 'swarm_facts', 'JoinTokens', 'Worker']) }}"
  run_once: true

- debug:
    msg: "{{ join_token_worker }}"
  run_once: true

输出如下所示:

TASK [deploy_docker : Get join-token for worker nodes] ********************************************************************************************************************************************************************************************************************************************************
ok: [eu-central-1a-01]

TASK [deploy_docker : debug] **********************************************************************************************************************************************************************************************************************************************************************************
ok: [eu-central-1a-01] => {
    "msg": "[AnsibleUndefined, AnsibleUndefined, AnsibleUndefined, 'SWMTKN-1-2xgm1l987hh18gbq0tc8vrwn209qlxge6nkwdq4pof2zd4e2vs-7f7ig2ama5amqq8iuii4o8xxo', AnsibleUndefined, AnsibleUndefined, 'SWMTKN-1-2xgm1l987hh18gbq0tc8vrwn209qlxge6nkwdq4pof2zd4e2vs-7f7ig2ama5amqq8iuii4o8xxo', AnsibleUndefined, AnsibleUndefined]"
}

我想从此列表中提取 token - 但我不知道如何过滤掉 AnsibleUndefined值(value)。我正在使用 docker_swarm模块获取 result .

Answer 1

让我们尽量减少这种情况。例如，剧本

- hosts: h1,h2,h3
  gather_facts: false
  vars:
    d2:
      h1:
        k1:
         k2: v1
      h2:
        k1:
          kX: v2
      h3:
        k1:
          k2: v3
  tasks:
    - debug:
        msg: "{{ ansible_play_hosts_all|
                 map('extract', d2, ['k1', 'k2'])|
                 list }}"
      run_once: true

给

  msg: '[''v1'', Undefined, ''v3'']'

有更多选择如何 “从列表中排除 AnsibleUndefined” .

使用选择(信用@mdaniel)

    - debug:
        msg: "{{ ansible_play_hosts_all|
                 map('extract', d2, ['k1', 'k2'])|
                 select|
                 list }}"
      run_once: true

给

  msg:
  - v1
  - v3

使用 regex_replace

    - debug:
        msg: "{{ ansible_play_hosts_all|
                 map('extract', d2, ['k1', 'k2'])|
                 map('regex_replace', '(.*)', '\\1')|
                 list }}"
      run_once: true

给

  msg:
  - v1
  - ''
  - v3

如果要创建字典，请迭代主机。例如

    - set_fact:
        worker_dict: "{{ worker_dict|default({})|
                         combine({item: d2[item].k1.k2|default('')}) }}"
      loop: "{{ ansible_play_hosts_all }}"
      run_once: true

给

  worker_dict:
    h1: v1
    h2: ''
    h3: v3