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r - 如何使用 facet_wrap 在每个方面具有不同数字的离散类别之间创建相等的距离

转载 作者:行者123 更新时间:2023-12-04 14:59:43 27 4
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我的目标是让图中所有国家之间的距离大致相等。例如,在第一类(增加)中,国家是分散的。另一方面,第二类和第三类国家之间的距离太近了。

这迫使我减小国家文本的大小(例如“IS”、“UK”...)和绘制的估计值(例如“1.5”、“1.2”...) .因此,一旦我将此文件提取为 pdf 或 word,读者就无法清楚地看到国家名称或估算值是什么。如果我增加它们的文本大小,那么这些国家/地区会重叠并且一些估计值(尤其是稳定类别的估计值)会触及它们旁边的其他估计值。

有没有办法解决这个问题?

enter image description here

这是数据和代码:

structure(list(cntry = structure(1:26, .Label = c("AU", "BE", 
"BG", "CY", "CZ", "DK", "EE", "GR", "ES", "FI", "FR", "HU", "IE",
"IS", "IT", "LT", "LV", "NL", "NO", "PO", "PT", "RO", "SE", "SV",
"SK", "UK"), class = "factor"), estimate = c(-4.08943257103804,
0.264307961887035, -0.4008773217117, -1.91874959282838, -0.964527079847473,
-4.30067253169461, -0.920426011686486, -0.0746109649703081, 1.03855028529355,
-1.28691260252507, -3.21446990383498, -0.0381504621278269, 0.0286675062078212,
1.46814093121697, -0.50165518722767, -0.787733440190981, 0.745627449639574,
0.586929625060384, 0.191285070657763, 0.217512744502688, 1.35842665232147,
0.358385446150237, -0.238203754070039, -1.59896322663246, 0.100424706108376,
1.15585740391863), conf.low = c(-5.60117192484885, -0.840219073796263,
-1.62699620711119, -3.64218275679053, -2.0989086744086, -6.58558173414225,
-2.11216930433376, -0.986944473894656, 0.221565068594325, -2.69498298777435,
-3.98554432677659, -1.10463119017979, -1.86828501326683, -1.18099254843252,
-1.27464693464705, -2.24155213350216, -0.522730236481673, -0.479328474807381,
-1.20651423960493, -0.461478316905123, -2.34340124131767, -0.458919023509462,
-1.65550186084418, -3.35325169024894, -1.17499651445811, 0.0527941744160207
), conf.high = c(-2.57769321722723, 1.36883499757033, 0.825241563687791,
-0.195316428866239, 0.169854514713651, -2.01576332924696, 0.271317280960783,
0.83772254395404, 1.85553550199278, 0.121157782724206, -2.44339548089336,
1.02833026592413, 1.92562002568248, 4.11727441086645, 0.271336560191708,
0.666085253120201, 2.01398513576082, 1.65318772492815, 1.58908438092046,
0.8965038059105, 5.0602545459606, 1.17568991580994, 1.1790943527041,
0.155325236984016, 1.37584592667486, 2.25892063342124), crisis_f = structure(c(3L,
2L, 2L, 3L, 3L, 3L, 3L, 2L, 1L, 3L, 3L, 2L, 2L, 1L, 3L, 3L, 1L,
1L, 2L, 2L, 2L, 2L, 2L, 3L, 2L, 1L), .Label = c("Increase", "Stable",
"Decrease"), class = "factor")), row.names = c(NA, -26L), class = "data.frame")

library(ggplot2)
library(dplyr)
library(forcats)

df %>%
arrange(estimate) %>%
mutate(label = replace(round(estimate, 1),cntry==1, '')) %>%
ggplot(aes(x= estimate, fct_reorder(cntry, estimate, .desc = TRUE),label=label)) +
geom_point()+
geom_text(hjust= -0.5, size=2.5) +
geom_linerange(mapping=aes(xmin=conf.low , xmax=conf.high, y=cntry), width=0.1, size=.5, color="black") +
geom_point(mapping=aes(x=estimate, y=cntry), size=2.3, shape=21, fill="black") +
geom_vline(xintercept=0, color = "black", linetype= "dotted") +
ggtitle(NULL) + xlab("Happiness") +
scale_y_discrete(expand = expansion(add = 1)) +
facet_wrap(vars(crisis_f), scales = "free_x", strip.position = "bottom", shrink=F) +
ylab("") +
theme_classic() +
theme(
plot.title = element_text(color="Black", size=24, face="bold", hjust= 0.5), axis.title.x = element_text(color="Black", size=24, face="bold"),
axis.title.y = element_text(color="Black", size=20, face="bold"),
axis.text.x = element_text(color="black", size=10),
axis.text.y = element_text(face="bold", color="black", size=14),
strip.text = element_text(face= "bold", size=17),
plot.caption = element_text(size= 12),
legend.justification=c(1,0),
legend.position=c(1,0),
strip.placement = "outside",
strip.background = element_rect(line = "solid"),
panel.spacing = unit(0, "mm")) +
coord_flip()

最佳答案

您可以使用 ggforce 中的 facet_row,它允许自由缩放和 strip.position='bottom':

library(ggplot2)
library(dplyr)
library(forcats)
library(ggforce)

p <- df %>%
arrange(estimate) %>%
mutate(label = replace(round(estimate, 1),cntry==1, '')) %>%
ggplot(aes(x= estimate, fct_reorder(cntry, estimate, .desc = TRUE),label=label)) +
geom_point()+
geom_text(hjust= -0.5, size=2.5) +
geom_linerange(mapping=aes(xmin=conf.low , xmax=conf.high, y=cntry), width=0.1, size=.5, color="black") +
geom_point(mapping=aes(x=estimate, y=cntry), size=2.3, shape=21, fill="black") +
geom_vline(xintercept=0, color = "black", linetype= "dotted") +
ggtitle(NULL) + xlab("Happiness") +
scale_y_discrete(expand = expansion(add = 1)) +
ylab("") +
theme_classic() +
theme(
plot.title = element_text(color="Black", size=24, face="bold", hjust= 0.5), axis.title.x = element_text(color="Black", size=24, face="bold"),
axis.title.y = element_text(color="Black", size=20, face="bold"),
axis.text.x = element_text(color="black", size=10),
axis.text.y = element_text(face="bold", color="black", size=14),
strip.text = element_text(face= "bold", size=17),
plot.caption = element_text(size= 12),
legend.justification=c(1,0),
legend.position=c(1,0),
strip.placement = "outside",
strip.background = element_rect(line = "solid"),
panel.spacing = unit(0, "mm")) +
coord_flip()

p + ggforce::facet_row(vars(crisis_f), scales = 'free_x', space = 'free',strip.position = 'bottom')

enter image description here

关于r - 如何使用 facet_wrap 在每个方面具有不同数字的离散类别之间创建相等的距离,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/67214247/

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