regex - 如何在Scala中拆分字符串但保持与正则表达式匹配的部分？

Question

我的问题和 Split string including regular expression match 一样但对于 Scala。不幸的是，JavaScript 解决方案在 Scala 中不起作用。

我正在解析一些文本。假设我有一些字符串:

"hello wold <1> this is some random text <3> foo <12>"

我想得到以下序列: "hello world" :: "<1>" :: "this is some random text" :: "<3>" :: "foo" :: "<12>" .

请注意，每当遇到 <"number"> 序列时，我都会拆分字符串。

Answer 1

val s = "hello wold <1> this is some random text <3> foo <12>"
s: java.lang.String = hello wold <1> this is some random text <3> foo <12>

s.split("""((?=<\d{1,3}>)|(?<=<\d{1,3}>))""")
res0: Array[java.lang.String] = Array(hello wold , <1>,  this is some random text , <3>,  foo , <12>)

你真的尝试过你的编辑吗？有 \d+不起作用。见 this question .

s.split("""((?=<\d+>)|(?<=<\d+>))""")
java.util.regex.PatternSyntaxException: Look-behind group does not have an obvious maximum length near index 19