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php - 如何在 PHP 更新中显示选中的复选框? postgresql

转载 作者:行者123 更新时间:2023-12-04 14:54:03 25 4
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我必须显示一个选中的复选框 (like this one) , 但目前从数据库中提取值 ( it shows this )

有没有办法在从数据库中提取已知值时显示选中的复选框(PgAdmin)(所有代码都是 HTML、CSS 或 PHP)

代码:THIS IS THE TABLE DATA

 Topings: <br>
<br>
<label class="checkbox-container">
<input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="Vanilla") echo "checked" ?> value="<?php echo $row['toping']; ?>">
<span class="checkmark"></span>
<span class="checkbox-txt"> Vanilla</span>
<br /></br>
</label>
<label class="checkbox-container">
<input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="Chocolate") echo "checked" ?>value="<?php echo $row['toping']; ?>">
<span class="checkmark"></span>
<span class="checkbox-txt">Chocolate</span>
<br /></br>
</label>
<label class="checkbox-container">
<input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="Caramel") echo "checked" ?>value="<?php echo $row['toping']; ?>">
<span class="checkmark"></span>
<span class="checkbox-txt">Caramel</span>
<br /></br>
</label>
<label class="checkbox-container">
<input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="Strawberry") echo "checked" ?>value="<?php echo $row['toping']; ?>">
<span class="checkmark"></span>
<span class="checkbox-txt">Strawberry</span>
<br /></br>
</label>
<label class="checkbox-container">
<input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="M&M's") echo "checked" ?>value="<?php echo $row['toping']; ?>">
<span class="checkmark"></span>
<span class="checkbox-txt">M&M's</span>
<br /></br>
</label>
<label class="checkbox-container">
<input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="Oreo") echo "checked" ?>value="<?php echo $row['toping']; ?>">
<span class="checkmark"></span>
<span class="checkbox-txt">Oreo</span>
<br /></br>
</label>
<label class="checkbox-container">
<input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="Meringue") echo "checked" ?>value="<?php echo $row['toping']; ?>">
<span class="checkmark "></span>
<span class="checkbox-txt">Meringue</span>
<br />
</label>

最佳答案

首先,您必须知道如何将多个复选框值存储到数据库中。如果您需要,我已经添加了引用。

假设您的 toppings保存为逗号分隔值,如下所示:

Comma-separated-toppings

  1. 您可以使用 explode()逗号分隔值展开为平面索引数组的函数。

    来自 Chocolate,Caramel,M&M's["Chocolate", "Caramel", "M&M's"] .

  2. 然后你可以使用in_array()用于检查项目(topping)是否在数组中可用或不可用的函数。

PHP

/* Connection with PDO */
// DB details (Change it to your DB details)
$host = '127.0.0.1';
$user = 'root';
$password = 'root';
$dbname = 'test';
$port = '3306';

// DataSourceName for MySQL (The one I used for testing)
$dsn = "mysql:dbname=$dbname;host=$host;port=$port";
// DataSourceName for PostgreSQL (Use this and add port if you need)
$dsn = 'pgsql:dbname=$dbname;host=$host;';

$pdo = new PDO($dsn, $user, $password);
/* End Connection String */

// Get Toppings Value From DB
$statement = $pdo->query("SELECT `toppings` FROM toppings");
$res = $statement->fetch();

//res[0] = Comma Separated String of Toppings: 'Topping1,Topping2,Topping3'
$toppings = explode(',', $res[0]);
// $toppings = Array of toppings checked: ["Topping1", "Topping2", "Topping3" ]


/* Connection with PG */
$db = pg_connect("host=localhost port=5432 dbname=SRIS user=postgres password=password");
$result = pg_query($db, "SELECT * FROM tablename ");
$row = pg_fetch_assoc($result);

$toppings = explode(',', $row['toppings']);

HTML 格式

<label class="checkbox-container">
<input type="checkbox" name="toping[]" <?=(in_array('Vanilla',$toppings) ? 'checked="checked"' : '')?> value="Vanilla">
<span class="checkmark"></span>
<span class="checkbox-txt"> Vanilla</span><br/></br>
</label>
<label class="checkbox-container">
<input type="checkbox" name="toping[]" <?=(in_array('Chocolate',$toppings) ? 'checked="checked"' : '')?> value="Chocolate">
<span class="checkmark"></span>
<span class="checkbox-txt">Chocolate</span><br/></br>
</label>
<label class="checkbox-container">
<input type="checkbox" name="toping[]" <?=(in_array('Caramel',$toppings) ? 'checked="checked"' : '')?> value="Caramel">
<span class="checkmark"></span>
<span class="checkbox-txt">Caramel</span><br/></br>
</label>
<label class="checkbox-container">
<input type="checkbox" name="toping[]" <?=(in_array('Strawberry',$toppings) ? 'checked="checked"' : '')?> value="Strawberry">
<span class="checkmark"></span>
<span class="checkbox-txt">Strawberry</span><br/></br>
</label>
<label class="checkbox-container">
<input type="checkbox" name="toping[]" <?=(in_array("M&M's",$toppings) ? 'checked="checked"' : '')?> value="M&M's">
<span class="checkmark"></span>
<span class="checkbox-txt">M&M's</span><br/></br>
</label>
<label class="checkbox-container">
<input type="checkbox" name="toping[]" <?=(in_array('Oreo',$toppings) ? 'checked="checked"' : '')?> value="Oreo">
<span class="checkmark"></span>
<span class="checkbox-txt">Oreo</span><br/></br>
</label>
<label class="checkbox-container">
<input type="checkbox" name="toping[]" <?=(in_array('Meringue',$toppings) ? 'checked="checked"' : '')?> value="Meringue">
<span class="checkmark "></span>
<span class="checkbox-txt">Meringue</span><br/>
</label>

注意:

  • 我已将 name 属性更改为 name=topping[] ,您应该使用字段名称数组
  • 我还更改了 value 属性,为每个复选框提供了一个预定值

引用资料:

关于php - 如何在 PHP 更新中显示选中的复选框? postgresql,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/68496284/

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