c++ - 如何使用 std::ranges 加入 View

Question

如何使用 std::ranges 连接两个 View ？
在 range-v3 中， View 与 views::concat() 结合在一起，我无法弄清楚如何使用 std::ranges 做到这一点。

#include <string>
#include <iostream>
#include <vector>
#include <ranges>
using namespace std;
using namespace views;

void snake_to_camel() {   
    auto transform = views::transform;
    auto const s = string{"feel_the_force"};
    auto words = s | split('_');                        // [[f,e,e,l],[t,h,e],[f,o,r,c,e]]
    auto words_cap = words | transform([](auto word){
        auto transform = views::transform;
        auto head = word | take(1) 
                         | transform([](unsigned char c){return toupper(c);}); // e.g. [F]
        auto tail = word | drop(1);                     // e.g. [e.e.l]
        return tail;
        //return concat( head, tail );                  // e.g. [F,e,e,l] // join( head, tail ) will not work here.
    });                                                 // [[F,e,e,l],[T,h,e],[F,o,r,c,e]]
    auto s_camelcase = words_cap | join;                // [F.e.e.l.T.h.e.F.o.r.c.e]
    string res;
    for(auto c : s_camelcase)
        res.push_back(c);
    cout << res;
}

int main() {
    snake_to_camel();
    cout << endl;
}

Answer 1

C++20 无法做到这一点。
但受益于P2328和 P2210 ，在C++23中，我们可以用另一种方式来做，即对分割 subrange 进行变换成string ，修改返回，最后join :

void snake_to_camel() {   
    auto transform = views::transform;
    auto const s = string{"feel_the_force"};
    auto words = s | split('_');                        // [[f,e,e,l],[t,h,e],[f,o,r,c,e]]
    auto words_cap = words | transform([](auto r) { 
                               std::string word(r);
                               word.front() = toupper(word.front());
                               return word;
                             });                        // [[F,e,e,l],[T,h,e],[F,o,r,c,e]]
    auto s_camelcase = words_cap | join;                // [F.e.e.l.T.h.e.F.o.r.c.e]
    string res;
    for(auto c : s_camelcase)
        res.push_back(c);
    cout << res;
}

Demo.