php - 使用 PHP 重命名 JSON 子项

Question

我正在尝试帮助现有项目中的 JSON 结构格式，目标是重命名一些子项而不是值。像这样的JSON格式

{
  "table-name": "Kiwi",
  "created-on": "November 20, 2021",
  "token": "lsUVozOB2TxhvMv",
  "icons": "default",
  "links": "default",
  "extra": "default",
  "mode": "Private",
  "collaborators": [],
  "columns": {
    "Name": {
      "type": "text",
      "extra": ""
    },
    "Info": {
      "type": "longtext",
      "extra": ""
    },
    "Status": {
      "type": "droplist",
      "extra": {
        "fr": "Pending",
        "sc": "On-going",
        "th": "Completed",
        "fo": "Cancelled"
      }
    }
  },
  "data": [{
      "Name": "Team Reports",
      "Info": "Submitting marketing materials reports",
      "Status": "Completed"
    },
    {
      "Name": "Fabia HR",
      "Info": "Brian asking for a report",
      "Status": "Pending"
    },
    {
      "Name": "Fabia",
      "Info": "Meeting with CEO @cafe 9:00",
      "Status": "Cancelled"
    }
  ]
}

我们正在研究列，将Name重命名为Task，同时保留另一个。使用 array push 和 slice 键后，我得到 0 作为键和“Task as subkeys like

"0":{
  "Task":{
    "type":"text",
    "extra":""
  },

代码如下所示。请在空闲时间分享您的解决方案，在此先感谢您，非常感谢您的关注。完全菜鸟在这里🖐PHP:

$file = file.json;  
$jsn = file_get_contents($file);
$data = json_decode($jsn, true);
 
//get name data array 
$sub_data = $data['columns']['Name'];

$new_rename = array(
    "Task" => $sub_data;
);

array_push($data['columns'],$new_rename);

//now delete old "Name";
array_slice($data['columns'],'Name')

//save stuff
$jsn = json_encode($data);
file_put_contents($file,$jsn);

Answer 1

鉴于您正在使用 JSON 对象，因此是 PHP 关联数组(与数字索引相反)，您真正需要做的就是设置新属性并取消设置旧属性

$data["columns"]["Task"] = $data["columns"]["Name"];
unset($data["columns"]["Name"]);

演示~ https://3v4l.org/7pBpZ