django - formfield_for_foreignkey 和内联管理员

Question

我只想在特定的比赛中展示与球队相关的球员。通常当我这样做时，它会从数据库中显示我所有的球员。这是我的models.py

class InningsCard(models.Model):
    fixture = models.ForeignKey(Fixture)
    team = models.ForeignKey(Team)
    runs = models.IntegerField(max_length=6, default=0)
    wickets = models.IntegerField(max_length=6, default=0)
    overs = models.FloatField(max_length=6, default=0.0)

    def __unicode__(self):
        return str(self.team)

class BattingDetail(models.Model):
    STATUS_CHOICES = (
        ('no', 'not out'),
        ('bowled', 'bowled'),
        ('caught', 'caught'),
        ('lbw', 'lbw'),
    )
    innings = models.ForeignKey(InningsCard)
    player = models.ForeignKey(Player)
    runs = models.IntegerField(max_length=5, default=0)
    status = models.CharField(max_length=15, choices=STATUS_CHOICES, default='no')

    def __unicode__(self):
        return str(self.player)

现在，这是我的 admin.py 包含 formfield_for_foreignkey，但它不起作用。

class BattingInline(admin.TabularInline):
    model = BattingDetail
    extra = 0

    def formfield_for_foreignkey(self, db_field, request=None, **kwargs):

        if db_field.name == 'player':
            kwargs = Player.objects.filter(team = request.team)
        else:
            pass

        return super(BattingInline, self).formfield_for_foreignkey(db_field, request, **kwargs)


class InningCardAdmin(admin.ModelAdmin):
    inlines = [BattingInline]

我哪里出错了？

//鼠

Answer 1

您正在替换整个 kwargs与查询集。 kwargs必须是字典，您要查找的特定键是“查询集”:

kwargs['queryset'] = Player.objects.filter(team=request.team)

我几乎肯定请求实际上不会有属性 team .除非您自己在此处未显示的某些代码中添加了它，否则您需要找到另一种方法来获取当前的“团队”。您可以从 request.path 解析出团队 ID并将其用于查找，例如。

作为旁注， else如果您只是要去 pass，则不需要此条款那里。