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python - 如何检查字符串枚举中是否存在字符串?

转载 作者:行者123 更新时间:2023-12-04 14:30:47 26 4
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我创建了以下枚举:

from enum import Enum

class Action(str, Enum):
NEW_CUSTOMER = "new_customer"
LOGIN = "login"
BLOCK = "block"
我继承自 str , 以便我可以做以下事情:
action = "new_customer"
...
if action == Action.NEW_CUSTOMER:
...
我现在希望能够检查字符串是否在此 Enum 中,例如:
if "new_customer" in Action:
....
我尝试将以下方法添加到类中:
def __contains__(self, item):
return item in [i for i in self]
但是,当我运行此代码时:
print("new_customer" in [i for i in Action])
print("new_customer" in Action)
我得到这个异常(exception):
True
Traceback (most recent call last):
File "/Users/kevinobrien/Documents/Projects/crazywall/utils.py", line 24, in <module>
print("new_customer" in Action)
File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/enum.py", line 310, in __contains__
raise TypeError(
TypeError: unsupported operand type(s) for 'in': 'str' and 'EnumMeta'

最佳答案

我今天刚碰到这个问题;我不得不为 Python 3.8 更改许多子包。
也许这里其他解决方案的替代方案如下,灵感来自优秀答案 here到一个类似的问题,以及@MadPhysicist 的 answer on this page :

class MetaEnum(EnumMeta):
def __contains__(cls, item):
try:
cls(item)
except ValueError:
return False
return True


class BaseEnum(Enum, metaclass=MetaEnum):
pass


class Stuff(BaseEnum):
foo = 1
bar = 5
测试 (在 py37 或 38 中):
>>> 1 in Stuff
True

>>> Stuff.foo in Stuff
True

>>> 2 in Stuff
False

>>> 2.3 in Stuff
False

>>> 'zero' in Stuff
False

关于python - 如何检查字符串枚举中是否存在字符串?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/63335753/

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