julia - 为什么十六进制或二进制数的类型是 Uint64 而十进制数的类型是 Int64？

Question

julia> typeof(-0b111)
Uint64

julia> typeof(-0x7)
Uint64

julia> typeof(-7)
Int64

我觉得这个结果有点令人惊讶。为什么数字的基数决定有符号或无符号？

Answer 1

看起来这是预期的行为:

This behavior is based on the observation that when one uses unsigned hex literals for integer values, one typically is using them to represent a fixed numeric byte sequence, rather than just an integer value.

http://docs.julialang.org/en/latest/manual/integers-and-floating-point-numbers/#integers

...似乎有点奇怪的选择。