java - 无法从 openapi 客户端中的字符串反序列化 `java.time.OffsetDateTime` 类型的值

Question

我有一个带有通过 gradle 插件生成的 Java 客户端的 Spring Boot 应用程序:

openApiGenerate {
    generatorName = "java"
    inputSpec = specsYml
    outputDir = "$buildDir/generated".toString()
    apiPackage = "com.customapi.api"
    invokerPackage = "com.customapi.invoker"
    modelPackage = "com.customapi.model"
    configOptions = [
        dateLibrary: "java8",
        library    : "resttemplate"
    ]
}

我选择了 "java8"如 dateLibrary因为这似乎是 Java 1.8 项目的首选。
使用生成的客户端，我正在执行一个请求，该请求返回一个包含时间戳的对象。
我收到以下错误:

java.lang.IllegalStateException: Failed to execute CommandLineRunner
    ...
Caused by: org.springframework.web.client.RestClientException: Error while extracting response for type [class com.customapi.model.Info] and content type [application/json];
    ...
Caused by: org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Cannot deserialize value of type `java.time.OffsetDateTime` from String "2020-07-21T12:12:23.000+0200": ...
   ...
...
Caused by: com.fasterxml.jackson.databind.exc.InvalidFormatException: Cannot deserialize value of type `java.time.OffsetDateTime` from String "2020-07-21T12:12:23.000+0200": Failed to deserialize java.time.OffsetDateTime: (java.time.format.DateTimeParseException) Text '2020-07-21T12:12:23.000+0200' could not be parsed at index 23
 at [Source: (ByteArrayInputStream); line: 1, column: 84] (through reference chain: com.customapi.model.Info["buildTimestamp"])
    at com.fasterxml.jackson.databind.exc.InvalidFormatException.from(InvalidFormatException.java:67) ~[jackson-databind-2.10.3.jar:2.10.3]
    at com.fasterxml.jackson.databind.DeserializationContext.weirdStringException(DeserializationContext.java:1679) ~[jackson-databind-2.10.3.jar:2.10.3]
    at com.fasterxml.jackson.databind.DeserializationContext.handleWeirdStringValue(DeserializationContext.java:935) ~[jackson-databind-2.10.3.jar:2.10.3]
    at com.fasterxml.jackson.datatype.jsr310.deser.JSR310DeserializerBase._handleDateTimeException(JSR310DeserializerBase.java:86) ~[jackson-datatype-jsr310-2.10.3.jar:2.10.3]
    at com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer.deserialize(InstantDeserializer.java:218) ~[jackson-datatype-jsr310-2.10.3.jar:2.10.3]
    at com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer.deserialize(InstantDeserializer.java:50) ~[jackson-datatype-jsr310-2.10.3.jar:2.10.3]
    at com.fasterxml.jackson.databind.deser.impl.MethodProperty.deserializeAndSet(MethodProperty.java:129) ~[jackson-databind-2.10.3.jar:2.10.3]
    at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:369) ~[jackson-databind-2.10.3.jar:2.10.3]
    at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:159) ~[jackson-databind-2.10.3.jar:2.10.3]
    at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:4218) ~[jackson-databind-2.10.3.jar:2.10.3]
    at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:3267) ~[jackson-databind-2.10.3.jar:2.10.3]
    at org.springframework.http.converter.json.AbstractJackson2HttpMessageConverter.readJavaType(AbstractJackson2HttpMessageConverter.java:269) ~[spring-web-5.2.7.RELEASE.jar:5.2.7.RELEASE]
    ... 17 common frames omitted
Caused by: java.time.format.DateTimeParseException: Text '2020-07-21T12:12:23.000+0200' could not be parsed at index 23
    at java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:1949) ~[na:1.8.0_151]
    at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1777) ~[na:1.8.0_151]
    at com.fasterxml.jackson.datatype.jsr310.deser.InstantDeserializer.deserialize(InstantDeserializer.java:212) ~[jackson-datatype-jsr310-2.10.3.jar:2.10.3]
    ... 24 common frames omitted

Info相关部分有问题的类(class):

...
@javax.annotation.Generated(value = "org.openapitools.codegen.languages.JavaClientCodegen", date = "2020-07-26T14:09:54.137+02:00[Europe/Berlin]")
public class Info {
    ...
    public static final String JASON_PROPERTY_BUILD_TIMESTAMP = "buildTimestamp";
    private OffsetDateTime buildTimestamp;
    ...
    public Info buildTimestamp(OffsetDateTime buildTimestamp) {
        this.buildTimestamp = buildTimestamp;
        return this;
    }

    public void setBuildTimestamp(OffsetDateTime buildTimestamp) {
        this.buildTimestamp = buildTimestamp;
    }
    ...
}

两种 setter 方法都接受 OffsetDateTime对象并且没有注释，因此转换必须在其他地方进行。输入字符串再次是“2020-07-21T12:12:23.000+0200”。
相关的依赖是

ext {
    swagger_annotations_version = "1.5.22"
    jackson_version = "2.10.3"
    jackson_databind_version = "2.10.3"
    jackson_databind_nullable_version = "0.2.1"
}

dependencies {
    compile "io.swagger:swagger-annotations:$swagger_annotations_version"
    compile "com.fasterxml.jackson.core:jackson-core:$jackson_version"
    compile "com.fasterxml.jackson.core:jackson-annotations:$jackson_version"
    compile "com.fasterxml.jackson.core:jackson-databind:$jackson_databind_version"
    compile "com.fasterxml.jackson.jaxrs:jackson-jaxrs-json-provider:$jackson_version"
    compile "org.openapitools:jackson-databind-nullable:$jackson_databind_nullable_version"
    compile "com.fasterxml.jackson.datatype:jackson-datatype-jsr310:$jackson_version"
}

jackson 和 java 8 似乎有很多问题，这个站点上的大多数解决方案似乎都在添加注释。但我怀疑修改生成的代码是正确的解决方案。生成客户端时我是否忽略了一个重要参数？服务器是否提供了错误的格式？我该如何调查？
更新:
当我切换时 dateLibrary至 legacy它有效，所以我想我收到了正确的数据。
(jaxrs) 服务器生成器中存在一个错误 https://github.com/swagger-api/swagger-codegen/issues/3648#issuecomment-244056314服务器发送格式错误(没有冒号) date-time .我的解决方案是对可以处理错误格式的客户端使用旧的 dateLibrary。

Answer 1

按照我在问题中的评论，我意识到您不需要 Jackson 注释。你只需要调整setter。这是一个基本的演示:
假设有以下类:

import java.time.OffsetDateTime;
//import com.fasterxml.jackson.annotation.JsonSetter;
import java.time.format.DateTimeFormatter;

public class MyOdt {
    
    private OffsetDateTime odt;

    public OffsetDateTime getOdt() {
        return odt;
    }

    //@JsonSetter("odt")
    public void setOdt(String odtString) {
        final String pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSxx";
        DateTimeFormatter dtfB = DateTimeFormatter.ofPattern(pattern);
        this.odt = OffsetDateTime.parse(odtString, dtfB);
    }
    
}

该类将从一个 JSON 片段创建，例如:

String jsonTest = "{ \"odt\" : \"2020-07-21T12:12:23.000+0200\" }";

对象映射器:

ObjectMapper objectMapper = new ObjectMapper()
        .registerModule(new JavaTimeModule())
        .disable(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS);

MyOdt odtTest = objectMapper.readValue(jsonTest, MyOdt.class);

作为引用，这是问题中的原始评论:

An observation: That is not a valid string to be parsed by OffsetDateTime.parse() because the default datetime format expects the offset to have a colon in it: +02:00. So, this works: OffsetDateTime.parse("2020-07-21T12:12:23.000+02:00")