vb6 - 如何只获取文件？

Question

如何仅从文件的完整路径获取文件名？

MY path -  C:\Documents and Settings\Arshad\My Documents\ravi.txt

Answer 1

看看这个: Retrieve Filename without Path or Extension .

这是上面链接中的函数:

Public Function GetFileName(flname As String) As String

    'Get the filename without the path or extension.
    'Input Values:
    '   flname - path and filename of file.
    'Return Value:
    '   GetFileName - name of file without the extension.

    Dim posn As Integer, i As Integer
    Dim fName As String

    posn = 0
    'find the position of the last "\" character in filename
    For i = 1 To Len(flname)
        If (Mid(flname, i, 1) = "\") Then posn = i
    Next i

    'get filename without path
    fName = Right(flname, Len(flname) - posn)

    'get filename without extension
    posn = InStr(fName, ".")
        If posn <> 0 Then
            fName = Left(fName, posn - 1)
        End If
    GetFileName = fName
End Function

输入时

C:\Documents and Settings\Arshad\My Documents\ravi.txt

这个函数返回

ravi

该函数是这样调用的:

Dim FileName As String
FileName = GetFileName("C:\Documents and Settings\Arshad\My Documents\ravi.txt")