WPF:功能区控制应用程序按钮和快速访问工具栏位置

Question

应用程序按钮和快速访问工具栏放置是如何完成的？

(来源:microsoft.com)

Answer 1

首先，在您的 xaml 中引用 Ribbon 命名空间...

<r:RibbonWindow
        ...
    xmlns:r="clr-namespace:Microsoft.Windows.Controls.Ribbon;assembly=RibbonControlsLibrary"
        >

然后您可以通过绑定(bind)到 ViewModel 上的 RibbonCommand 属性来配置您的应用程序菜单(与绑定(bind)其他 Ribbon 命令非常相似)

<r:Ribbon>
    <r:Ribbon.ApplicationMenu>
        <r:RibbonApplicationMenu
            Command="{Binding Path=ApplicationMenuCommand}">

        <!-- If your first menu item if 'Open File' -->
            <r:RibbonApplicationMenuItem
                Command="{Binding Path=OpenFileCommand}" />

        </r:RibbonApplicationMenu>
    </r:Ribbon.ApplicationMenu>
</r:Ribbon>

属性看起来像这样的地方:

public RibbonCommand OpenFileCommand
{
    get
    {
        if (_openFileCommand == null)
        {
            _openFileCommand = new RibbonCommand("OpenFileCommand", typeof(RibbonApplicationMenuItem));
            _openFileCommand.LabelDescription = "Label Description";
            _openFileCommand.LabelTitle = "Label Title";
            _openFileCommand.ToolTipDescription = "Tooltip Description";
            _openFileCommand.ToolTipTitle = "Tooltip Title";

            _openFileCommand.CanExecute += (sender, e) => { e.CanExecute = true; };
            _openFileCommand.Executed += (sender, e) => { /* logic to open a file goes here... */; };
        }
        return _openFileCommand;
    }
}

对于您问题的第二部分-恐怕我还没有使用 QuickAccess 工具栏玩太多，但我猜它会以类似...

<r:Ribbon.QuickAccessToolBar>
    <r:RibbonQuickAccessToolBar>
     <!-- put your RibbonCommands here -->
    </r:RibbonQuickAccessToolBar>
</r:Ribbon.QuickAccessToolBar>