json - 如何在jq中多次分配字段值？

Question

我有这样的 jq 命令:

jq --arg ts "$TS" '.Date = $ts, .Marker.Date = $ts, .InfoFromTerminator.Timestamp = $ts'

但它似乎只替换了最后一项，保持前两项不变。如何重写查询以替换所有 3 个参数？

Answer 1

逗号是 jq 中的运算符:

Even the comma operator is a generator, generating first the values generated by the expression to the left of the comma, then for each of those, the values generate by the expression on the right of the comma.

可以通过从一个过滤器/分配管道到下一个过滤器/分配来更改多个元素，如下所示:

jq --arg ts "$TS" '.Date = $ts | .Marker.Date = $ts | .InfoFromTerminator.Timestamp = $ts'