python-3.x - 在 python 中创建子图 plotly

Question

我对 python 和 ploty 相当陌生(此时实际编码时间不到 3 个月)。
我试图在 plotly 中创建子图。我已经使用下面的代码(也附在下面的代码片段)中创建了图表，但我似乎无法使用子图让它们工作

我创建了许多这些类型的数据图，任何有助于收紧我的代码的帮助将不胜感激。

这是一个示例数据集(下面是我知道如何在本网站上排列的唯一方法？？)[注意:它与我用来生成以下图表的数据集不同，但足够接近]:

subjid_raw  studyarm    visit             pn_chg     fx_chg   totw_chg

20001       B           02_ASCRN              -1       -28      -30
20001       B           02_DAY001              0         0        0
20001       B           02_DAY029WK4         -12       -56      -76
20001       B           02_DAY092WK13        -17       -61      -88
20001       B           02_DAY183WK26        -19       -64      -93
20001       B           02_DAY274WK39        -13       -45      -65
20001       B           02_ZEOS              -22       -70     -102
20001       B           MTH06                -22       -74     -108
20001       B           MTH12                -23       -74     -109
20005       C           02_ASCRN               3         8       12
20005       C           02_DAY001              0         0        0
20005       C           02_DAY029WK4         -20       -80     -112
20005       C           02_DAY092WK13        -16       -68      -95
20005       C           02_DAY183WK26        -22       -69      -99
20005       C           02_DAY274WK39        -19       -71     -103
20005       C           02_ZEOS               -4       -26      -36
20005       C           MTH06                -17       -76     -105
20005       C           MTH12                -22       -72     -106
20007       D           02_ASCRN             -13         2      -12
20007       D           02_DAY001              0         0        0
20007       D           02_DAY029WK4           6       -15      -45
20007       D           02_DAY092WK13        -10       -26      -39
20007       D           02_DAY183WK26        -19       -72      -97
20007       D           02_DAY274WK39         -4       -30      -35
20007       D           02_ZEOS              -25       -71     -103
20007       D           MTH12                -24       -85     -117
20010       A           02_ASCRN              -5        -2       -6
20010       A           02_DAY001              0         0        0
20010       A           02_DAY029WK4         -24       -75     -102
20010       A           02_DAY092WK13         -3         1       -1
20010       A           02_DAY183WK26         -2         7        6
20010       A           02_DAY274WK39          1         9       13
20010       A           02_ZEOS                -6       -1       -7

需要:我想让子图显示为具有两行两列的子图(尽管我不确定这是否可行，因为只有三列数据要绘制？？)

import pandas as pd ##(version: 0.22.0)
import numpy as np ##(version: 1.14.0)

import plotly.graph_objs as go
import plotly.tools as tls
from plotly.offline import *    
import cufflinks as cf ##(version: 0.12.1)

init_notebook_mode(connected=True)
cf.go_offline()



dummy_data = pd.read_csv("desktop\dummy_data.csv")

a = dummy_data.groupby(['studyarm', 'visit']) ['fx_chg'].mean().unstack('studyarm').drop(['02_UNSCH','ZEOS'])
b = dummy_data.groupby(['studyarm', 'visit']) ['pn_chg'].mean().unstack('studyarm').drop(['02_UNSCH','ZEOS'])
c = dummy_data.groupby(['studyarm', 'visit']) ['totw_chg'].mean().unstack('studyarm').drop(['02_UNSCH','ZEOS'])

fig3 = a.iplot(kind='line', yTitle='Score', title='Dummy Data1', mode=markers, asFigure=True)
fig3['data'][0]['marker']['symbol'] = 'hexagram-open-dot'
fig3['data'][1]['marker']['symbol'] = 'circle-dot'
fig3['data'][2]['marker']['symbol'] = 'star-open-dot'
fig3['data'][3]['marker']['symbol'] = 'square'
iplot(fig3, filename='simple-plot')

fig4 = b.iplot(kind='line', yTitle='Score', title='Dummy Data2', mode=markers, asFigure=True)
fig4['data'][0]['marker']['symbol'] = 'hexagram-open-dot'
fig4['data'][1]['marker']['symbol'] = 'circle-dot'
fig4['data'][2]['marker']['symbol'] = 'star-open-dot'
fig4['data'][3]['marker']['symbol'] = 'square'
iplot(fig4, filename='simple-plot')

fig5 = c.iplot(kind='line', yTitle='Score', title='Dummy Data3', mode=markers, asFigure=True)
fig5['data'][0]['marker']['symbol'] = 'hexagram-open-dot'
fig5['data'][1]['marker']['symbol'] = 'circle-dot'
fig5['data'][2]['marker']['symbol'] = 'star-open-dot'
fig5['data'][3]['marker']['symbol'] = 'square'
iplot(fig5, filename='simple-plot')

## I have tried all forms of 
##fig = tls.make_subplots(rows=n, cols=n) ##but it just shows graphs as blank?  

任何帮助或朝着正确方向轻推将不胜感激。

<iframe width="900" height="800" frameborder="0" scrolling="no" src="//plot.ly/~t3c/29.embed"></iframe>

<iframe width="900" height="800" frameborder="0" scrolling="no" src="//plot.ly/~t3c/31.embed"></iframe>

<iframe width="900" height="800" frameborder="0" scrolling="no" src="//plot.ly/~t3c/34.embed"></iframe>

Answer 1

你可以只用袖扣'subplot功能。据我所知，没有相关文档。

cf.subplots([fig3, fig4, fig5],
             shape=(2,2)).iplot()

会给你: