flask - View 函数未返回有效响应。 flask 棉花糖，RestAPI

Question

这个问题在这里已经有了答案:





Return JSON response from Flask view

(14 个回答)


去年关闭。




我在 Flask 上写申请.对于 RestAPI我在用 flask-marshmallow .但我得到错误。

The view function did not return a valid response. The return type must be a string, dict, tuple, Response instance, or WSGI callable, but it was a list. I do everything as in the example https://flask-marshmallow.readthedocs.io/en/latest/

class ApplicationSchema(ma.Schema):
    class Meta:
        fields = ("id", "name")

applications_schema = ApplicationSchema(many=True)

@bp.route("")
def applications():
    all_applications = Application.query.all()
    return applications_schema.dump(all_applications)

Answer 1

我能够通过将返回放在 jsonify 中来纠正这个问题。您可以从 flask 中导入它，它看起来像这样:

from flask import jsonify

@bp.route("")
    def applications():
        all_applications = Application.query.all()
        return jsonify(applications_schema.dump(all_applications))