compiler-errors - 莎士比亚变量分配不起作用

Question

我浏览了莎士比亚的一些文档，但无法弄清楚如何使莎士比亚程序正常工作。

我尝试了以下方法:

Shakespeare, A Program.
Romeo, A young man.
Juliet, a young woman
Act I: A test of variables.
Scene I: The first scene.
[Enter Romeo and Juliet]
Hamlet: You are as stupid as a smelly big flower! 

(这应该将Juliet设置为4，因为臭味= * 2，大= * 2，花= 1)

Juliet: Proceed to Scene II.
[Exeunt]
Scene I: The second scene.
[Enter Romeo and Juliet]
Juliet: Am I better than you?
Romeo: If so, you are as intelligent as the square root of Juliet.
Romeo: Open your heart.

这应该返回2，这是朱丽叶的值。不幸的是，这只会产生编译器错误。我究竟做错了什么？

Answer 1

一开始，您仅定义了Romeo和Juliet，并且具有2个场景I。我认为你的意思是

Shakespeare, A Program.

Romeo, A young man.
Juliet, a young woman.

Act I: A test of variables.

Scene I: The first scene.
[Enter Romeo and Juliet]
Romeo: <<This is important, because Hamlet is not defined!
You are as stupid as a smelly big flower!
Juliet: Proceed to Scene II.
[Exeunt]  

Scene II: The second scene. <<You need to change it to Scene II!
[Enter Romeo and Juliet] 
Juliet: Am I better than you?
Romeo: If so, you are as intelligent as the square root of Juliet.
Romeo: Open your heart.
[Exeunt]

这应该返回2。