python - 每个句子有多少个单词，如何得到意思？

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我有一个函数，想返回 (a) 每个句子的单词数和 (b) 元组列表中每个句子的平均单词长度。我可以得到(a)。对于(b)我可以得到每个句子的总字符数，但不是平均值。

我已经查看了一些帖子 ( this ,
that和
another ) 但我无法理解这最后一块。

我已经将一些失败的尝试注释掉了。

import statistics

def sentence_num_and_mean(text):
    """ Output list of, per sentence, number of words and mean length of words """
    # Replace ! and ? with .
    for ch in ['!', '?']:
        if ch in text:
            text = text.replace(ch, '.')

    # Number of words per sentence
    num_words_per_sent =  [len(element) for element in (element.split() for element in text.split("."))]

    # Mean length of words per sentence

    # This gets sum of characters per sentence, so on the right track
    mean_len_words_per_sent = [len(w) for w in text.split('.')]

    # This gives me "TypeError: unsupported operand type(s) for /: 'int' and 'list'" error
    # when trying to get the denominator for the mean
    # A couple efforts
    #mean_len_words_per_sent = sum(num_words_per_sent) / [len(w) for w in text.split('.')]
    #mean_len_words_per_sent = [(num_words_per_sent)/statistics.mean([len(w) for w in text.split()])]

    # Return list zipped together
    return list(zip(num_words_per_sent, mean_len_words_per_sent))

驱动程序:

split_test = "First sentence ends with a period. Next one ends with a question mark? Another period. Then exclamation! Blah blah blah"
func_test = sentence_num_and_mean(split_test)
print(split_test)
print(func_test)

哪个打印

First sentence ends with a period. Next one ends with a question mark? Another period. Then exclamation! Blah blah blah
[(6, 33), (7, 35), (2, 15), (2, 17), (3, 15)]

一方面，我需要去掉空格和句点，但暂时忽略这一点，如果我正确地进行了简单的数学运算，它应该是:

[(6, 5.5), (7, 5), (2, 7.5), (2, 8.5), (3, 5)]

Answer 1

更好的变量名称可能会帮助您阐明如何表达这些想法。text.split('.')给你什么？句子列表 (str)。
如果在名为 sentence 的变量中有一个句子然后 sentence.split()给你一个单词列表(str)。考虑到这些，这很容易编写。
mean_len_words_per_sent = [statistics.mean(len(word) for word in sentence.split()) for sentence in text.split('.')]