python - 计算某些文本中多字子串的出现次数

Question

因此，对于某些文本中的单个单词子串计数，我可以使用 some_text.split().count(single_word_substring) .对于某些文本中的多字子串计数，我该如何做到这一点？
例子:

text = 'he is going to school. abc is going to school. xyz is going to school.'
to_be_found = 'going to school'

计数应为 3。

text = 'he is going to school. abc is going to school. xyz is going to school.'
to_be_found = 'going to'

计数应为 3。

text = 'he is going to school. abc is going to school. xyz is going to school.'
to_be_found = 'go'

计数应为 0。

text = 'he is going to school. abc-xyz is going to school. xyz is going to school.'
to_be_found = 'school'

计数应为 3。

text = 'he is going to school. abc-xyz is going to school. xyz is going to school.'
to_be_found = 'abc-xyz'

计数应为 1。
假设1:一切都是小写的。
假设2:文本可以包含任何内容。
假设3:被发现的也可以包含任何东西。例如， car with 4 passengers , xyz & abc ， 等等。
注意:基于 REGEX 的解决方案是可以接受的。我只是好奇是否可以不使用正则表达式(很高兴拥有并且仅供将来可能对此感兴趣的其他人)。

Answer 1

这是使用正则表达式的工作解决方案:

import re

def occurrences(text,to_be_found):
    return len(re.findall(rf'\W{to_be_found}\W', text))

正则表达式中的大写 W 用于非单词字符，包括空格和其他标点符号。