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flutter - 为什么像这样分配 Future 函数时 pumpAndSettle 超时

转载 作者:行者123 更新时间:2023-12-04 13:29:15 26 4
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在我的 State 课上,我宣布了一个 future :

Future<void> _testFuture;
并在 initState 中分配它像这样:
super.initState();

_testFuture = Future(() async {
await Future.value(1); //can be any computation
});
并在 FutureBuilder 中使用它像这样:
 FutureBuilder(
future: _testFuture,
builder: (context, snapshot) {
if (snapshot.connectionState == ConnectionState.done)
return Text('Hi');
else
return Center(
child: CircularProgressIndicator(),
);
},
),
这在使用 flutter run 正常运行应用程序时工作正常但是当我尝试使用 flutter test test/widget_test.dart 测试小部件时:
void main() {
testWidgets('Testing', (WidgetTester tester) async {
// Build our app and trigger a frame.
await tester.runAsync(() async {
await tester.pumpWidget(MyApp());
await tester.pumpAndSettle();
});
}
它失败了:
══╡ EXCEPTION CAUGHT BY FLUTTER TEST FRAMEWORK ╞════════════════════════════════════════════════════
The following assertion was thrown while running async test code:
pumpAndSettle timed out
但是,如果我以这种方式分配 future ,则相同的测试将毫无问题地通过:
super.initState();

Future<void> testFutures() async {
await Future.value(1);
}

_testFuture = testFutures();
分配 future 的两种方式有什么区别?

最佳答案

pumpAndSettle 的默认超时时间是十分钟,如 docs 中所述.检查您的代码,测试应该运行良好。正在初始化 Future<void>当我在本地尝试时,无论哪种方式都不应该引起任何问题。
这是您也可以尝试的示例。文本应显示一次 Future.delayed()完成。 Future<void>其中之一在 initState() 上初始化.

import 'package:flutter/material.dart';

void main() {
runApp(MyApp());
}

class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return MaterialApp(
title: 'Flutter Demo',
theme: ThemeData(
primarySwatch: Colors.blue,
),
home: MyHomePage(title: 'Flutter Demo Home Page'),
);
}
}

class MyHomePage extends StatefulWidget {
MyHomePage({Key? key, required this.title}) : super(key: key);

final String title;

@override
_MyHomePageState createState() => _MyHomePageState();
}

class _MyHomePageState extends State<MyHomePage>

late Future<void> _testFuture1;

Future<void> _testFuture2() async {
// await Future.value(1);
await Future.delayed(Duration(seconds: 5), () {
debugPrint('Test 2: \"Hello from the future!\"');
});
}

@override
void initState() {
super.initState();
_testFuture1 = Future(() async {
// await Future.value(1);
await Future.delayed(Duration(seconds: 5), () {
debugPrint('Test 1: \"Hello from the future!\"');
});
});
}

FutureBuilder _futureBuilder1() {
return FutureBuilder(
future: _testFuture1,
builder: (BuildContext context, AsyncSnapshot<dynamic> snapshot) {
if (snapshot.connectionState == ConnectionState.done)
return Text('Test 1 Done!');
else
return Center(
child: CircularProgressIndicator(),
);
// return Text('Test 1 Done!');
});
}

FutureBuilder _futureBuilder2() {
return FutureBuilder(
future: _testFuture2(),
builder: (BuildContext context, AsyncSnapshot<dynamic> builder) {
return Text('Test 2 Done!');
});
}

@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text(widget.title),
),
body: Center(
child: Column(
mainAxisAlignment: MainAxisAlignment.center,
children: <Widget>[
_futureBuilder1(),
_futureBuilder2(),
],
),
),
);
}
}
这是测试文件
void main() {
testWidgets('Future test', (WidgetTester tester) async {
// Build our app and trigger a frame.
await tester.runAsync(() async{
await tester.pumpWidget(MyApp());
await tester.pump(); // both pump() and pumpAndSettle() works fine
}).then((value) {
// expect(find.text('Test 1 Done!'), findsOneWidget);
// expect(find.text('Test 2 Done!'), findsOneWidget);
});
});
}
Demo
测试
Test
这是我的 Flutter 版本供引用
[✓] Flutter (Channel stable, 2.2.1, on macOS 11.4 20F71 darwin-x64)
• Flutter version 2.2.1
• Framework revision 02c026b03c (6 weeks ago), 2021-05-27 12:24:44 -0700
• Engine revision 0fdb562ac8
• Dart version 2.13.1

关于flutter - 为什么像这样分配 Future 函数时 pumpAndSettle 超时,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/66095251/

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