javascript - 使用正则表达式查找我选择的前两个相同字符之间的文本

Question

Assume the following output

.

20198818-119903 | firmware-check | passed: host test-1000 is connected to a test with Version: 333 | |
20198818-119903 | other-test-123 | passed: host test-1000 is connected to a test with 333:
20198818-119903 | test4| passed :| host | is connected to a test with 333
20198818-119903 | something | passed: host test-1000 is connected to a test with Version:

I want to extract firmware-check, other-test-123, test4, and something

所以基本上 一切之间 前两个竖条。

我试图用 txt2re 解决这个问题，但没有按照我想要的方式工作(例如不忽略第三行的主机)。我从未使用过正则表达式，也不想仅针对这种特殊情况学习它。有人能帮助我吗？

Answer 1

你可以用这个

^[^|]+\|([^|]+)

let str = `20198818-119903 | firmware-check | passed: host test-1000 is connected to a test with Version: 333 | |
20198818-119903 | other-test-123 | passed: host test-1000 is connected to a test with 333:
20198818-119903 | test4| passed :| host | is connected to a test with 333
20198818-119903 | something | passed: host test-1000 is connected to a test with Version:`

let op = str.match(/^[^|]+\|([^|]+)/gm).map(m=> m.split('|')[1].trim())

console.log(op)