蛋糕PHP 3.0 : How to do an insert on duplicate key update?

Question

我有一个数组 $articles像这样

[
    (int) 0 => [
        'id' => '-@940039',
        'xe_dsca' => 'ÜP2768G/1',
        'xe_citg' => '1F0200',
        'xe_cuni' => 'stk',
        'xe_seak' => 'ÜP2768G/1',
        'xe_seab' => '',
        'xe_wght' => '0.0153',
        'xe_cwun' => 'kg',
        'xe_wgap' => '2',
        'xe_seri' => '2',
        'xe_ltct' => '2',
        'xe_qual' => '2',
        'xe_hama' => '2',
        'xe_ctyo' => 'DE',
        'xe_ccde' => '85045095',
        'xe_cpln' => '240000',
        'xe_spar' => '2',
        'xe_wear' => '2',
        'xe_ctyo_de' => null,
        'xe_cean' => null,
        'xe_ewm_dsce' => null,
        'xe_cood' => null,
        'xe_ewm_dsne' => null,
        'xe_ewm_dsge' => null,
        'xe_ewm_dsen' => null,
        'xe_ewm_dscz' => null,
        'xe_wgh1' => null,
        'xe_wgh2' => null,
        'xe_wgh3' => null
    ],
    (int) 1 => [
        'id' => '000-000500-00000',
        'xe_dsca' => 'DUMMY ZEITBUCHUNG',
        'xe_citg' => '1F0800',
        'xe_cuni' => 'stk',
        'xe_seak' => 'DUMMY ZEITBUCHUN',
        'xe_seab' => '000-000500-00000',
        'xe_wght' => '0',
        'xe_cwun' => 'kg',
        'xe_wgap' => '2',
        'xe_seri' => '2',
        'xe_ltct' => '2',
        'xe_qual' => '2',
        'xe_hama' => '2',
        'xe_ccde' => '000',
        'xe_cpln' => '930000',
        'xe_spar' => '2',
        'xe_wear' => '2',
        'xe_ctyo' => null,
        'xe_ctyo_de' => null,
        'xe_cean' => null,
        'xe_ewm_dsce' => null,
        'xe_cood' => null,
        'xe_ewm_dsne' => null,
        'xe_ewm_dsge' => null,
        'xe_ewm_dsen' => null,
        'xe_ewm_dscz' => null,
        'xe_wgh1' => null,
        'xe_wgh2' => null,
        'xe_wgh3' => null
    ]

在我的 Controller 中，我有这些行

foreach ($articles AS $article) {
    $query = $this->Articles->query();
    $query
        ->insert($required_article_fields)
        ->values($article)
        ->execute();
}

这段代码工作正常，但有没有人建议我如何在重复 key 更新时插入？一次保存多行数据的最佳做法是什么？

Answer 1

您可以使用查询 epilog()方法

foreach ($articles AS $article) {
  $query = $this->Articles->query();
  $query
    ->insert($required_article_fields)
    ->values($article)
    ->epilog('ON DUPLICATE KEY UPDATE field=field+1')
    ->execute();
}

如果需要安全地传递值，还可以将 QueryExpression 对象传递给该方法。