c# - 将参数发布到 api 主体返回错误 403

Question

我有一个 API，它需要 postman 中的 body 参数，我得到 200OK 并得到结果，但在 .netcore 中，我收到错误 403 forbidden，

 var openPaymentesRequest = new CreatePaymentInitiationRequest()
        {
            CreditorAccount = new CreatePaymentInitiationRequest.CreditorAccounts()
            {
                Iban= "SE1230000000000000000002",

            },
            CreditorName = "Merchant123",
            DebtorAccount = new CreatePaymentInitiationRequest.DebtorAccounts()
            {

                Iban= "SE1230000000000000000001"
            },
            InstructedAmount = new CreatePaymentInitiationRequest.InstructedAmounts()
            {
                Amount = "123.50",
                Currency = "SEK"
            }
            ,
            RemittanceInformationUnstructured = ""
        };

我将对象序列化:

 var json = JsonConvert.SerializeObject(openPaymentesRequest);

我创建了一个查询字符串:

  StringContent queryString = new StringContent(json, Encoding.UTF8, "application/json");

最后我传递了查询字符串，但我不确定我是否传递给正文，希望你能帮助我

var responseString = await _httpClient.PostAsync("https://api.co", queryString);

我发布的标题

_httpClient.DefaultRequestHeaders.Authorization = new AuthenticationHeaderValue("Bearer", token.Token);
        _httpClient.DefaultRequestHeaders.Add("X-Request-ID", guid.ToString());
        _httpClient.DefaultRequestHeaders.Add("X-BicFi", "ESSESESS");
        _httpClient.DefaultRequestHeaders.Add("PSU-IP-Address", "192.168.0.0");
        _httpClient.DefaultRequestHeaders.Add("PSU-User-Agent", "mozilla/4.0");

对于 guid，我生成它并不重要，它只是一个随机数。

Answer 1

尝试添加

var contentType = new MediaTypeWithQualityHeaderValue("application/json");
_httpClient.DefaultRequestHeaders.Accept.Add(contentType);

我会尝试删除，因为我不知道它是做什么用的

        _httpClient.DefaultRequestHeaders.Add("X-Request-ID", guid.ToString());
        _httpClient.DefaultRequestHeaders.Add("X-BicFi", "ESSESESS");
        _httpClient.DefaultRequestHeaders.Add("PSU-IP-Address", "192.168.0.0");
        _httpClient.DefaultRequestHeaders.Add("PSU-User-Agent", "mozilla/4.0");