arrays - 将数组传递给 OpenCL 中的函数参数

Question

如何将数组传递给 OpenCL 中的函数？我在行 c[n]=FindIndexFromArray(a,3); 中收到错误“..”类型“_global float *”的参数与“float *”类型的参数不兼容；

float FindIndexFromArray(float myArray[], float Key)
{
    // simple looping to find the index
    for (int i=0;i<sizeof(myArray);i++)
       if (myArray[i]==Key)
         return i; 

}

kernel void ProcessArray(
    global read_only float* myArray,
    global read_only float* Key,
    global write_only float* c )
{
    int index = get_global_id(0); 
    c[index] = FindIndexFromArray(myArray, Key); // How do I pass myArray parameter?
}

我编辑的源代码:

float FindIndexFromArray(__global read_only float* myArray[], __global read_only float* Key)
{
    // simple looping to find the index
    for (int i=0;i<sizeof(myArray);i++)
       if (myArray[i]==Key)
         return i; 

}

kernel void ProcessArray(
    __global read_only float* myArray,
    __global read_only float* Key,
    __global write_only float* c )
{
    int index = get_global_id(0);
    c[index] = FindIndexFromArray(myArray, Key); // How do I pass myArray parameter?
}

Answer 1

它如错误消息中所述。您的 myArray和 Key自带类型 global和 read-only ，因此您必须在将其传递给另一个函数时声明相同的类型。总之你的FindIndexFromArray应该

FindIndexFromArray(global read_only float* myArray, global read_only float* Key)