typescript :包装泛型类的函数返回类型

Question

我无法使用 Typescript 以通用方式解决这个问题，我将不胜感激任何帮助!

• 工厂应该部署合约
• CustomFactory 是一个工厂，应该部署一个 CustomContract(即契约(Contract))
• MockFactory 应该是所有这些逻辑的包装器

目标就是这样(半伪代码)

interface MockFactory<F extends Factory> extends F {
    deploy: (...args: Parameters<F.prototype.deploy>) => MockContract<F.prototype.deploy.returnValue>
}

为了更好地说明问题，我创建了一个 Playground在哪里可以看到错误

Answer 1

刚刚通过使用 ReturnType 和 Parameters 解决了，还需要将接口(interface)转换为类型:

interface Contract {}

interface Factory {
    deploy: (...args: any[]) => Contract;
}

class CustomContract implements Contract {}

class CustomFactory implements Factory {
    deploy(x: number, y: number): CustomContract {
        return {};
    }
}

type MockContract<C extends Contract> = Contract & C & {
    mockProperty: number;
}

type MockFactory<F extends Factory> = F & {
    // deploy should have the parameters of the function deploy inside F (in this case CustomFactory)
    // deploy should return a MockContract of the return type of the function deploy inside F (MockContract<CustomContract> in a generic way)
    deploy: (...args: Parameters<F['deploy']>) => MockContract<ReturnType<F['deploy']>>
}

const example: MockFactory<CustomFactory> = {} as any;
example.deploy(1, 2);

Updated Playground